To find the maximum or minimum value of a function, we can find the derivative of the function, set it equal to 0, and solve for the critical points.
H'(t) = -32t + 64
Now find the critical numbers:
-32t + 64 = 0
-32t = -64
t = 2 seconds
Since H(t) has a negative leading coefficient, we know that it opens downward. This means that the critical point is a maximum value rather than a minimum. If we weren't sure, we could check by plugging in a value for t slightly less and slighter greater than t=2 into H'(t):
H'(1) = 32
H'(3) = -32
As you can see, the rate of change of the object's height goes from increasing to decreasing, meaning the critical point at t=2 is a maximum.
To find the height, plug t=2 into H(t):
H(2) = -16(2)^2 +64(2) + 30 = 94
The answer is 94 ft at 2 sec.
Answer:
2/5
Step-by-step explanation:
5/5 = full job
3/5 = done
full job - done = remaining
5/5 job - 3/5 job
= 2/5 (remaining)
A dotted line is not included in the solution so there is no equal sign.
The blue area is to the right of the dotted line so the solution is >
The line crosses the x axis at -2
The answer is : x-y > -2
Answer:
43/18
Step-by-step explanation:
2/3(1/3+ 3 1/4)
2/3(1/3+ 3 1/4)
find the lowest common denominator (12) to add the two fractions.
1/3= 4/12;
3 1/4= 13/4 = 39/12
4/12+ 39/12= 43/12
2/3(43/12)
- Then multiply the fractions.
2/3(43/12)
Numerator: 2*43= 86
Denominator: 3*12= 36
86/36
- Last simplify your fraction.
43/18 or 2 7/18
Step-by-step explanation:
Since, y varies directly as x:
