I think it is 64. you add all of them together and hten divide it by 6.
<h2>Solving Equations</h2>
To solve linear equations, we must perform inverse operations on both sides of the equal sign to <em>cancel values out</em>.
- If something is being added to x, subtract it from both sides.
- If something is being subtracted from x, add it on both sides.
- Same with multiplication and division. If x is being divided, multiply. If x is being multiplied, divide.
We perform inverse operations to<em> combine like terms</em>. This means to get x to one side and everything else on the other.
<h2>Solving the Questions</h2><h3>Question 1</h3>

Because 7 is being added to x, subtract it from both sides:

Because x is being multiplied by 5, divide both sides by 5:

Therefore.
.
<h3>Question 2</h3>

Here, we can group all the x values on the left side of the equation. Subtract 5x from both sides:

To isolate x, subtract 4 from both sides:

Divide both sides by 2:

Therefore,
.
For this case we have the following equation:
w = F • PQ
Where,
w: work done
F: is the force vector
PQ: is the vector of the direction of movement.
Rewriting the equation we have:
w = || F || • || PQ || costheta
Substituting values:
w = (60) * (100) * (cos (45))
w = (60) * (100) * (root (2) / 2)
w = 4242.640687 lb.ft
Answer:
The work done pushing the lawn mower is:
w = 4242.6 lb.ft
The inequality
gives the least number of buses, b, needed for the trip. The least number of buses is 9
<u>Solution:</u>
Given that, There are 412 students and 20 teachers taking buses on a trip to a museum.
Each bus can seat a maximum of 48.
We have to find which inequality gives the least number of buses, b, needed for the trip?
Now, there are 412 students and 20 teachers, so in total there are 412 + 20 = 432 travelers
<em><u>The number of buses required “b” is given as:</u></em>


Number of buses required ≥ 9 buses.
But least number will be 9 from the above inequality.
Hence, the inequality
gives least count of busses and least count is 9.
Answer: 80%
Step-by-step explanation: