Question

If tan a = 9／40use trigonometric identities to find the values of sin a and cos a.​

Answer 1

Answer:

see explanation

Step-by-step explanation:

Given

tan a = $\frac{9}{40}$ = $\frac{opposite}{adjacent}$

We require the hypotenuse h

Using Pythagoras' identity

h² = 9² + 40² = 81 + 1600 = 1681 ( take square root of both sides )

h = $\sqrt{1681}$ = 41 , thus

sin a = $\frac{opposite}{hypotenuse}$ = $\frac{9}{41}$

cos a = $\frac{adjacent}{hypotenuse}$ = $\frac{40}{41}$