The area of poster is 32 square inches
<em><u>Solution:</u></em>
Let "a" be the length of rectangle
Let "b" be the width of rectangle
<em><u>The length of Joseph’s rectangular poster is two times it’s width</u></em>
Therefore,
Length = 2 times width
a = 2b --------- eqn 1
The perimeter is 24 inches
<em><u>The perimeter of rectangle is given by formula:</u></em>
<em><u>Substituting the given values we get,</u></em>
Substitute b = 4 in eqn 1
a = 2(4)
a = 8
Thus we got,
Length = 8 inches
Width = 4 inches
<em><u>The area of rectangle is given by formula:</u></em>
Thus area of poster is 32 square inches
Answer:
false
Step-by-step explanation:
cost and selling price are the same thing so there would be no difference in percentage
Answer is:
6162 years
Explanation:
The given equation to use is:
<span>N=Noe^-kt
First, we will need to define the variables of the equation as follows:
No : original amount of C-14 (at t=0)
N : amount of C-14 at certain time (t)
k : a constant equals </span><span>0.0001
t : the time in years
Now, we are given that:
The skeleton contains 54% of it's original amount of C-14. This means that:
N/No = 54% = 0.54
Substitute with this given in the equation given, we will find that the only unknown is the time (t). We can now solve for t as follows:
</span><span>N=Noe^-kt
This can be rewritten as:
N/No = </span>e^-kt
Now,
N/No = e^-kt
0.54 = e^(-0.0001t)
Take ln for both sides:
ln (0.54) = -0.0001t
-0.61618 = -0.0001t
t = 6161.86 years which is approximately 6162 years
Hope this helps :)
Answer:
This is odd since the answer is 9 units. The best option would most likely be D since that is the closet answer. Unless it tells you to round i would go with D.
Step-by-step explanation: