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Ilia_Sergeevich [38]
2 years ago
13

Arlene Frank is saving money for her college

Mathematics
2 answers:
Ludmilka [50]2 years ago
6 0
With all respect may you say or continue the question do we can help you out. Thank you so very much
lora16 [44]2 years ago
3 0
Can you please include a question please? Thank you
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There are 52 runners in a race. How many ways can the runners finish​ first, second, and​ third?
elena55 [62]

Answer:

126

Step-by-step explanation:

52 * 3 = 126

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3 years ago
How to reflect over y axis in an equation?
iren [92.7K]
<span>1)  y = -f(x) (This is the reflection about the x-axis of the graph y = f(x).)  That is for every point (x, y) there is a point (x, -y).
</span><span>2)  y = |f(x)| means that the entire graph will be above the x-axis.  Why?  (The absolute value is always positive, that's why!!)<span>  To graph the absolute value graph, graph the function y = f(x).  Anything above the x-axis, stays above it, anything below the x-axis is reflected above the x-axis and anything on the x-axis, stays on the x-axis.
</span></span><span>3)  y = f(-x)  (This is reflection about the y-axis of the graph y = f(x))  For every point on the right of the y-axis, there is a point equidistant to the left of the y-axis.  That is for every point (x, y), there is a point (-x, y).  
</span><span>4)  Reflections about the line y = x is accomplished by interchanging the x and the y-values.  Thus for y = f(x) the reflection about the line y = x is accomplished by x = f(y).  Thus the reflection about the line y = x for y = x2 is the equation x = y2. </span>
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3 years ago
What did the exponent say to the base? Riddle
Vanyuwa [196]

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Why are you timesing me IDK

Step-by-step explanation:


4 0
3 years ago
( HELP? Will Mark :) )
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4

Step-by-step explanation:


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3 years ago
Find the value of x and the value of y
steposvetlana [31]

Answer:

B.   x = 7, y = 4√2

Step-by-step explanation:

Drop a vertical from the upper left corner

This creates a rectangle and a 45-45-90 triangle

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Therefor

x = 4 + 3

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y = 4√2

4 0
2 years ago
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