Answer: The cats cost more
also there is a typo
Step-by-step explanation:
I bought 1 dog and 3 cats a total cost of $7.75. the three cats cost more so in all the cats must cost 3.56$
Answer:
=7/6
Step-by-step explanation:
Join 4/3=1:7/3
7/3/2
Apply the fraction rule:=
7/3x2
Multiply the numbers=
7/6
Answer:
D
Step-by-step explanation:
.......................
To solve this problem, let us first assign some
variables. Let us say that:
x = pigs
y = chickens
z = ducks
From the problem statement, we can formulate the
following equations:
1. y + z = 30 --->
only chicken and ducks have feathers
2. 4 x + 2 y + 2 z = 120 --->
pig has 4 feet, while chicken and duck has 2 each
3. 2 x + 2 y + 2 z = 90 --->
each animal has 2 eyes only
Rewriting equation 1 in terms of y:
y = 30 – z
Plugging this in equation 2:
4 x + 2 (30 – z) + 2 z = 120
4 x + 60 – 2z + 2z = 120
4 x = 120 – 60
4 x = 60
x = 15
From the given choices, only one choice has 15 pigs. Therefore
the answers are:
She has 15 pigs, 12 chickens, and 18 ducks.
B: 2 and 1/6.
Tricky one if you rush through, its meant to SEEM complicated, like a lot of math questions.
