Distance formula is like pythagoren ahtoerem
D=

the distance between oints (x1,y1) and (x2,y2) is
D=

(2,8) and (7,5)
D=

D=

D=

D=

apxos
D=5.8309....
round
D=5.8 units
Answer:
Which of the following is a common sign that a chemical change has occurred?
Step-by-step explanation:
rodrickkkkkkkkkkkkkk
Answer:
A ) The money which Andre pay for the bike is $ 67.30
B ) The money which Andre pay for the bike is $ 76.92
Step-by-step explanation:
Given as :
The wholesale cost or market price of the bike = m.p = $ 96.15
A ) The discount percentage = 30 %
Let The selling price of the bike after discount = s.p
Now ,
Discount % = 
or, 30 % = 1 - 
or,
= 1 - 
Or,
= 1 - 
or,
= 
Or,
= 
Or, s. p =
× 96.15
∴ s.p = $ 67.305
So, He will pay $ 67.30
Hence The money which Andre pay for the bike is $ 67.30 . Answer
B ) If the bike is discounted by 20 % , let The selling price = s.p'
So,
Discount % = 
or, 20 % = 1 - 
or,
= 1 - 
Or,
= 1 - 
or,
= 
Or,
= 
Or, s. p' =
× 96.15
∴ s.p' = $ 76.92
So, He will pay $ 76.92
Hence The money which Andre pay for the bike is $ 76.92 . Answer