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3 years ago

What’s the area of the triangle

Mathematics

2 answers:

Ostrovityanka [42]3 years ago

7 0

<em>The formula for area of a triangle is bh × 1/2.</em>

(b) Base: 7

(h) Height: 24

24 × 7 × 0.5 = 84

The area of the triangle is 84 units²

Brut [27]3 years ago

7 0

Answer:

84 units squared

Step-by-step explanation:

Formula is A=Bh÷2

24 x 7 = 168

168 ÷ 2 = 84

24 is the base

7 is the height

Have a great day hope his helped good luck :)

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What is the interest on a loan of $7,850 that is borrowed at 6.55% for 18 months?

Flauer [41]

Answer:

${ \tt{simple \: interest = }} \\ { \tt principle \times rate \times period}\\ \\ = 7850 \times 6.55\% \times 18 \\ { \tt{interest = 925515 \: dollars}}$

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3 years ago

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A circle has the order pairs (-1, 2) (0, 1) (-2, -1) what is the equation . Show your work.

olga55 [171]

We know that:

$(x-a)^2+(y-b)^2=r^2$

is an equation of a circle.

When we substitute x and y (from the pairs we have), we'll get a system of equations:

$\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}$

and all we have to do is solve it for a, b and r.

There will be:

$\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}\\\\\\
\begin{cases}1+2a+a^2+4-4b+b^2=r^2\\a^2+1-2b+b^2=r^2\\4+4a+a^2+1+2b+b^2=r^2\end{cases}\\\\\\
\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\\\\\
$

From equations (II) and (III) we have:

$\begin{cases}a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\--------------(-)\\\\a^2+b^2-2b+1-a^2-b^2-4a-2b-5=r^2-r^2\\\\-4a-4b-4=0\qquad|:(-4)\\\\\boxed{-a-b-1=0}$

and from (I) and (II):

$\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\end{cases}\\--------------(-)\\\\a^2+b^2+2a-4b+5-a^2-b^2+2b-1=r^2-r^2\\\\2a-2b+4=0\qquad|:2\\\\\boxed{a-b+2=0}$

Now we can easly calculate a and b:

$\begin{cases}-a-b-1=0\\a-b+2=0\end{cases}\\--------(+)\\\\-a-b-1+a-b+2=0+0\\\\-2b+1=0\\\\-2b=-1\qquad|:(-2)\\\\\boxed{b=\frac{1}{2}}\\\\\\\\a-b+2=0\\\\\\a-\dfrac{1}{2}+2=0\\\\\\a+\dfrac{3}{2}=0\\\\\\\boxed{a=-\frac{3}{2}}$

Finally we calculate $r^2$ :

$a^2+b^2-2b+1=r^2\\\\\\\left(-\dfrac{3}{2}\right)^2+\left(\dfrac{1}{2}\right)^2-2\cdot\dfrac{1}{2}+1=r^2\\\\\\\dfrac{9}{4}+\dfrac{1}{4}-1+1=r^2\\\\\\\dfrac{10}{4}=r^2\\\\\\\boxed{r^2=\frac{5}{2}}$

And the equation of the circle is:

$(x-a)^2+(y-b)^2=r^2\\\\\\\left(x-\left(-\dfrac{3}{2}\right)\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}\\\\\\\boxed{\left(x+\dfrac{3}{2}\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}}$

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3 years ago

Help me plz <br> what´s 1000×1000=<br> thanks!!!

inn [45]

The answer is 1,000,000

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2 years ago

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The price of a company's share dropped by 3.50% by the end of the first year, down to $44.25. During the second year the price o

omeli [17]

Answer:

a. $45.86

b. $43.87

c. Percentage change = -4.40%)

Step-by-step explanation:

a. Let the price of share at the beginning of first year be represented with X

Now, Price of company's share dropped by 3.50% at the end of first year.

So, Price of share at the end of first year = x - 3.5% of x

= x - 0.035x

= 1x - 0.035x

= 0.965x

But it is equal to $44.25

=> 0.965x = 44.25

x = 44.25 / 0.965

x = 45.8549223

x = $45.86

b. During second year price of share decreased by $1.99. Therefore, Price of share at the end of second year = $45.86 - $1.99 = $43.87

c. Percentage change in the price of shares over two years = {(45.86 - 43.87)/45.86} *100

= (1.99/45.86)*100

= 0.04339294 * 100

= 4.40%

Now, as price of shares has dropped, the percentage change will be negative. (Δ% = -4.40%)

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2 years ago

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3 years ago

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