50%. students (in percent) who passed the second exam also passed the first exam.
Let's imagine that there are 100 kids in the teacher's class. We know that 40 of them passed BOTH tests, and 80 passed the second test.
Because if they weren't, they wouldn't have passed the first test and consequently wouldn't have passed both, we can be sure that the group of students who passed BOTH tests is only made up of the 80 who passed the second test.
Thus, both tests were passed by 40 of the 80 pupils who passed the second one:
40/80 = 1/2 = 50%.
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your answer would be all numbers
let me show you:
step 1) 6 more than 4 is 10
step 2) two times the sum of one-half the number plus three is 2*(2+3)
step 3) 2+3 is 5,and 5*2 is 10
step 4) compare the answers from steps 1 and 3,they are both 10
so your answer is ALL numbers
Answer:
y=x+1
Step-by-step explanation:
The slop and y-int are 1, just like on the graph
Multiple both ratios by a least common denominator
the least common denominator for both is 15
multiply the first ratio by 3/3
9/15=9/15
both are equal because when multiplying by the least common denominator you get the same answer
Answer:
it ix 23 then 43
Step-by-step explanation:
