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ozzi
3 years ago
9

Shirley has a credit card that uses the previous balance method. The opening

Mathematics
2 answers:
vesna_86 [32]3 years ago
8 0

Answer:

= $44.19

Step-by-step explanation:

APR = 19%

Billing cycle = 30 days

Balance = $2830

Let's first find the daily rate,

Daily rate =  \frac{0.19}{365} = 0.000521

The daily rate = 0.000521

To calculate the amount Shirley was charged interest for the billing cycle, we use:

Daily rate * billing cycle * balance

Where,

Daily rate

=  \frac{0.19}{365}

Billing cycle = 30 days

Balance = $2830

Therefore, expression to be used =

(\frac{0.19}{365}  * 30) * 2830 \\= $44.19

Artist 52 [7]3 years ago
3 0

Answer:

0.19× 2830

Step-by-step explanation:

APR= APR rate×total expenditure/100

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32%

Step-by-step explanation:

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3 years ago
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Suppose that a researcher is designing a survey to estimate the proportion of adults in your state who oppose a proposed law tha
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Answer:

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So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

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The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

Solution to the problem

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)  

The margin of error desired for this case is ME= \pm 0.02 equivalent to 2% points

For this case we need to assume a confidence level, let's assume 95%. And since we don't have prior estimation for the population proportion of interest the best value to do an approximation is \hat p =0.5

In order to find the critical value we need to take in count that we are finding the margin of error for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:  

z_{\alpha/2}=\pm 1.96  

Now we have all the values needed and if we replace into equation (b) we got:

n=\frac{0.5 (1-0.5)}{(\frac{0.02}{1.96})^2}= 2401

So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

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3 years ago
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Luden [163]

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D. No balance transfer fee

Step-by-step explanation:

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