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4 years ago

How many servings are in a 2 gallon container

1 answer:

8 0

On average if you were to serve it to people. There would be 16 servings out of a 2 gallon containers. So if it was a 2 gallon container of milk, 16 cups of milk would be served. I hope this helped you! :D

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Find the (a) mean, (b) median, (c) mode, and (d) midrange for the given sample data. An experiment was conducted to determin

egoroff_w [7]

Answer:

The mean phenotype code is 2.72

The median phenotype code is 2.52

The mode phenotype code is 2.

The midrange of the phenotype codes is 2.52

B Only the mode makes sense since the data is nominal.

Step-by-step explanation:

5 0

3 years ago

What is the name of the shapes A,B,D

artcher [175]

Answer:

i believe the bottom is a irregular quadrilateral and the first one is a parallelogram

Step-by-step explanation:

4 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Clim_%7Bx%5Cto%20%5C%200%7D%20%5Cfrac%7B%5Csqrt%7Bcos2x%7D-%5Csqrt%5B3%5D%7Bcos3x%7D%20%7D%7

salantis [7]

Answer:

$\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{1}{2}$

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

L'Hopital's Rule

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

We are given the limit:

$\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)}$

When we directly plug in x = 0, we see that we would have an indeterminate form:

$\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{0}{0}$

This tells us we need to use L'Hoptial's Rule. Let's differentiate the limit:

$\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)}$

Plugging in x = 0 again, we would get:

$\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \frac{0}{0}$

Since we reached another indeterminate form, let's apply L'Hoptial's Rule again:

$\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)}$

Substitute in x = 0 once more:

$\displaystyle \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)} = \frac{1}{2}$

And we have our final answer.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

6 0

3 years ago

What is the inverse of the function below?

vodomira [7]

Answer: C

Step-by-step explanation: With inverse equations, you switch y and x (y=f(x)) and undo/reverse the steps towards x.

1. Multiply by 3

2. Add 2

Equation by itself

0. x

1. 3(x)

2. 3(x+2)

8 0

4 years ago

Read 2 more answers

susan surveys 20 people in her math class to find out the most popular movie. 5 students say star wars if the are 200 students i

Eva8 [605]

5 out of 20 like Star Wars so what value (x) should like Star Wars out of 200. Set up a proportion comparing the two.

x= # of people in 7th gr who like Star Wars

5/20= x/200
cross multiply

(5*200)= (20*x)
1000= 20x
divide both sides by 20

50= x

ANSWER: 50 people in the 7th grade should like Star Wars.

Hope this helps! :)

8 0

4 years ago

Read 2 more answers