Answer:
The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 10 - 1 = 9
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 2.2622
The margin of error is:
M = T*s = 2.2622*0.3 = 0.68
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 98.44 - 0.68 = 97.76 ºF
The upper end of the interval is the sample mean added to M. So it is 98.44 + 0.68 = 99.12 ºF
The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF
Answer:
<h3>QUESTION;</h3>
This data set represents the number of cups of flour used in different recipes.
What is the mean of this data set?
{12, 13, 23, 112}
Enter your answer as a fraction in simplest form in the box.
___ cups
<h3>ANSWER</h3><h3> 13 po </h3>
Step-by-step explanation:
<h3>#Carryonlearing</h3>
Answer:
Questions 13-15 will all be related to the same situation.
A food pantry is making packages. Each package weighs 64 pounds. Each package contains 4 boxes. Each box contains a 7-pound bag of beans and a bag of rice. The bags of rice are all identical.
Which equation accurately represents this situation?
Step-by-step explanation:
I believe it would be $4,399.15 because if you use the formula I=P*R*T
P=62,845
R=0.07 or 7%
T=1 year period
So overall your equation is 62845*0.07*1=$4,399.15
Now at this point the interest is added onto the principal amount to figure out some new amount after one year so:
62845.00+4399.15=$67,244.15
