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4 years ago

9

Need help on this it uses ounces and money!

1 answer:

gayaneshka [121]4 years ago

5 0

If brand Y costs .02 more then it cost 1.67 per ounce.

1.67 * 15 is 25.05

15 ounces of brand Y cost $15.05

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In AABC shown below, L is the midpoint of BC, M is the midpoint of AB, and N is the midpoint of

sergij07 [2.7K]

Answer:

<h3>35</h3><h3 />

Step-by-step explanation:

see attached image.

perimeter of trapezoid = sides (6 + 8 + 5 + 8 + 8)

= 35

8 0

4 years ago

Which pair of ratios is proportional?

sergey [27]

The answer is = d due to the proportional

8 0

3 years ago

What is 2/3 cups of 2 cups

VikaD [51]

Well, you know in math, if you say "what is this number of this number?" It always means you multiply those two numbers. So 2/3 of 2 cups would be saying the same if I said 2/3 cups times 2 cups. Anyways, the answer would be 1.3 with a bar notation over the 3.

5 0

3 years ago

The density of silver is 10.5 g/cm. Find the volume of a silver bar if it’s mass is 950 g.

denis-greek [22]

Answer: The volume is 90.47 $cm^{3}$

Step-by-step explanation:

1. To solve this problem you need to use the formula for calculate the density, which is shown below:

$d=\frac{m}{V}$

Where $m$ is the mass and $V$ is the volume.

2. You must solve for the volume, as following:

$V=\frac{m}{d}$

3. Now, you must substitute the values of the mas and the density, which are given in the problem. Therefore, you have:

$V=\frac{950g}{0.5g/cm^{3}}\\V=90.47cm^{3}$

7 0

3 years ago

Quadrilateral ABCD has vertices A (-3, 0), B (2, 4), C (3, 1), and D (-4, -3). Calculate the perimeter of the quadrilateral. Rou

Andru [333]

Answer:

Perimeter of the Quadrilateral=20.78

Step-by-step explanation:

Perimeter of the Quadrilateral= AB+BC+CD+AD

Finding the sides of the quadrilateral using the Distance formula:

A(-3,0), B(2,4), C(3,1) and D(-4,-3)

$AB=\sqrt{(2-(-3))^2+(4-0)^2}\\\\ =\sqrt{(2+3)^2+4^2}\\\\ =\sqrt{5^2+4^2} \\\\=\sqrt{25+16}\\\\ =\sqrt{41}\\$

$=6.40$

BC=

$\sqrt{(3-2)^2+(1-4)^2} \\\\=\sqrt{1^2+(-3)^2} \\\\=\sqrt{1+9}\\\\ =\sqrt{10}$

$=3.16$

$CD=\sqrt{(-4-3)^2+(-3-1)^2} \\\\=\sqrt{(-7)^2+(-4)^2} \\\\=\sqrt{49+16}\\\\=\sqrt{65}\\\\ =8.06$

$AD=\sqrt{(-4-(-3))^2+(-3-0)^2} \\\\=\sqrt{(-4+3)^2+(-3)^2} \\\\=\sqrt{(-1)^2+(-3)^2} \\\\=\sqrt{1+9}\\\\=\sqrt{10} \\\\ =3.16$

Perimeter of the quadrilateral= AB+BC+CD+AD

=6.40+3.16+8.06+3.16

=20.78

6 0

3 years ago