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bulgar [2K]
3 years ago
8

Describe the difference between the set of whole numbers and the set of natural numbers?

Mathematics
2 answers:
larisa86 [58]3 years ago
7 0
Whole number- is zero and positive integers and Natural numbers- are counting numbers example (1,2,3,4.....) natural numbers do not contain 0
neonofarm [45]3 years ago
7 0

The set of counting numbers is called the set of natural numbers.

(1, 2, 3, 4, 5, 6, 7, 8, 9, 10)

When we include 0 in the set of natural numbers, the new set is called whole numbers.

(0, 1, 2, 3, 4, 5, 6, 7)

All natural numbers are included in the set of whole numbers. We can represent the relationship between these two sets of numbers using a diagram.

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LM = LN
3x - 2 = 2x + 1
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LM = LN = 7

MN = 5x - 2 = 13

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The distribution is <u>positively skewed</u>.

Step-by-step explanation:

It's not symmetric because the distribution in the chart isn't equally shown or marked. It's not negative skewed either because for it to be negative the graph would have to go down in a negative direction, usually the left, but in the picture you posted the graph is going down in the right direction. Lastly, positively skewed graphs or charts look like the one you posted. They go down in the right direction, hence why they're called "positively" skewed. The right tail of the distribution is longer in positively skewed graphs or charts.

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It costs $300 to join the new Superfit Gym.You then pay $15 each month and $2 each time you work out Carlo thinks he will use th
tankabanditka [31]

Answer:


Step-by-step explanation:

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5 0
3 years ago
Roger can run one mile in 18 minutes. jeff can run one mile in 15 minutes. if jeff gives roger a 1 minute head start, how long w
gladu [14]

Alright, lets get started.

Roger can run one mile in 18 minutes.

Jeff can run one mile in 15 minutes.

Suppose in x minutes, they both will catch up.

Roger runs in 18 minutes = 1 mile

So, Roger will run in 1 minute = \frac{1}{18} miles

So, Roger will run in x minutes = \frac{x}{18} miles

Jeff runs in 15 minues = 1 mile

So, Jeff will run in 1 minute = \frac{1}{15} mile

As Jeff gives roger a 1 minute head start, means Jeff will have x-1 minute time to run

So, Jeff will run in (x-1) minute = \frac{x-1}{15}

As both are cathing up means they both runs same distance, means

\frac{x}{18} =\frac{x-1}{15}

Cross Multiplying

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3 x = 18

x = 6 minutes

So for calculating distance = speed * time

Distance = \frac{1}{18} *6 = \frac{1}{3} miles

It means it will take 1/3 or 0.33 miles before jeff catches up to roger.   :   Answer

Hope it will help :)



4 0
3 years ago
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