3 years ago

4(x+3)= -24 solve for x

Mathematics

1 answer:

san4es73 [151]3 years ago

5 0

See attached.

Hope this helps!

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2= 7/9 x 6 + b solve for b

netineya [11]

Answer:

8/3

Step-by-step explanation:

7/9 x 6

14/3

14/3 - 2

8/3

5 0

3 years ago

(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

8 0

3 years ago

Solve for a: am=n+p <br><br> Help me

ss7ja [257]

Answer:

a = (n + p)/m

Step-by-step explanation:

just divide by m on both sides

hope this helped!

6 0

3 years ago

4) 16 + 7 + 9 = 7 + 9 + 16 *

nlexa [21]

Answer:

a.) Commutative Property of addition

Step-by-step explanation:

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2 years ago

Read 2 more answers

The elevation of city a is 80 feet below sea level, the elevation of city c is 16 feet below sea level. The elevation of city D

tekilochka [14]

I am almost positive that the answer could be 8 feet below sea level

6 0

2 years ago