Answer:
I think the answer for that question is c
Answer:
f(x) x^3 - 2x^2 + 5x + 12
Step-by-step explanation:
Next time please share the goal. I'm guessing your intent was to multiply out the given function.
f(x) = (x^2 + x - 3x - 3)(x - 4), or
= (x^2 - 2x - 3)(x - 4)
Now apply the distributive property of multiplication:
f(x) = x^3 - 4x^2 - 2x^2 + 8x - 3x + 12, or
= x^3 - x^2(4 - 2) + x(5) + 12, or
f(x) x^3 - 2x^2 + 5x + 12
Answer:
2
Step-by-step explanation:
Answer:
<h2><u><em>The function basically returns the same objects (= does nothing). This could also be written explicitly as a named function. new Function <- function(x) { x } which would then be. cross val <- function(data, lambda=0, y trans = new Function) This is the default value, like in lambda=0, except the default value is a function itself.</em></u></h2><h2><u>
brainlist plz </u></h2>
Step-by-step explanation:
