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Debora [2.8K]
3 years ago
10

Add the matrices to find the answer.

Mathematics
1 answer:
gayaneshka [121]3 years ago
7 0

Answer:

\large \boxed{\mathrm{Option \ C}}

Step-by-step explanation:

{\mathrm{view \ attachment}}

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Simplify x+2/x^2+2x-3 divide by x+2/x^2-x
ira [324]

\dfrac{\frac{x+2}{x^2+2x-3}}{\frac{x+2}{x^2-x}}

If x\neq-2, then we can immediately cancel the factors of x+2:

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Factorize the numerator and denominator:

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Next, if x\neq1, then

\dfrac{x^2-x}{x^2+2x-3}=\dfrac{x(x-1)}{(x+3)(x-1)}=\dfrac x{x+3}

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