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shepuryov [24]
4 years ago
7

Solve the system of equations using the linear combination method. {5m+3n=41 {3m−6n=9 Enter your answers in the boxes. m = n =

Mathematics
1 answer:
Masja [62]4 years ago
8 0
These are linear equations that can be solved simultaneously;
5m+3n=41
3m-6n=9   (multiplying the first equation by 3 and the second by 5)

15m+9n=123
15m-30n= 45 (subtracting the two equations)
         39n = 78
             n = 2, 
and for m, 3m = 9+6(2)
                        = 21
                     m = 7
Therefore, n=2 and m=7
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What is the solution for this inequality? 3(x-4)&gt;5(x-2)-8
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Find the volume of the cone in cubic feet. Use 3.14 for it and round your answer to the nearest tenth.
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<h3><u>Ⲁⲛ⳽ⲱⲉⲅ</u><u>:</u></h3>

\quad\hookrightarrow\quad \sf {5,790,806.5\:ft^3 }

<h3><u>Ⲋⲟⳑⳙⲧⳕⲟⲛ:</u></h3>

Here, we area provided a cone with:

  • Radius = 48m
  • Height = 68 m

We have to find the volume of the cone in feet³, and we are given that 1m = 3.2808ft

<h3><u>Ⳙ⳽ⲓⲛⳋ ⳨ⲟⲅⲙⳙ</u><u>ⳑɑ</u><u>:</u></h3>

The volume of a cone is equal to one third of the volume of a cylinder having the same base radius and height ,i.e:

\quad\longrightarrow\quad \sf { V =\dfrac{1}{3}\pi r^2 h }

<u>Therefore</u><u>,</u><u> </u><u>Volume:</u>

\implies\quad \tt {V = \dfrac{1}{3}\pi r^2 h }

\implies\quad \tt { V =\dfrac{1}{3}\times 3.14 \times 48^2 \times 68 }

\implies\quad \tt { V =\dfrac{1}{\cancel{3}}\times 3.14\times \cancel{2304} \times 68}

\implies\quad \tt {V =3.14\times 768\times 68 }

\implies\quad \tt {V = 163,983.36}

\implies\quad \tt { V = 163,983.36 \times (3.2808)^3 \qquad\quad\bigg[ As, \: 1m = 3.2808ft\bigg]}

\implies\quad \tt {V = 163,983.36\times 35.30 }

\implies\quad\underline{\pmb{ \tt { V = 5,790,806.5 ft^3}}}

‎ㅤ‎ㅤ‎ㅤ~<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u>,</u><u> </u><u>the </u><u>volume </u><u>of </u><u>given </u><u>cone </u><u>is </u><u>5,790,806.5</u><u> </u><u>f</u><u>t</u><u>³</u><u>.</u>

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Question 1
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The more accurate the better, giving brainliest to best answer
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The trapezoid has a height of 3in. a shorter base measuring 2.75 in and a longer base measuring 4.25 in. the total area is 10.5 in^2
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