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beks73 [17]
2 years ago
15

Need answer to the question in the picture above

Mathematics
1 answer:
densk [106]2 years ago
8 0

Answer:

solution given :

Since opposite side and side of a congruent triangle are equal.

Now

the statement which is true is:

<HDG=~ <HFE

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I need help with this math problem
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Step-by-step explanation:

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1 year ago
Which sum or difference identity would you use to verify that cos (180° - q) = -cos q?
Phantasy [73]

Answer:

\cos (a-b)=\cos a \cos b+\sin a \sin b

Step-by-step explanation:

 Given : \cos (180^{\circ}-q)=-\cos q

We have to write which identity we will use to prove the given statement.

Consider \cos (180^{\circ}-q)=-\cos q

Take left hand side of given expression \cos (180^{\circ}-q)

We know

\cos (a-b)=\cos a \cos b+\sin a \sin b

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Substitute , we get,

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Also, we know \sin 180^{\circ}=0 and \cos 180^{\circ}=-1

Substitute, we get,

\cos (180^{\circ}-q)=-1\cdot \cos (q)+\sin q \cdot 0

Simplify , we get,

\cos (180^{\circ}-q)=-\cos (q)

Hence, use difference identity to  prove the given result.

7 0
3 years ago
Read 2 more answers
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