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Andreas93 [3]
4 years ago
10

F=G (m×M)/r^(2); solve for r

Mathematics
1 answer:
eimsori [14]4 years ago
4 0

Multiply by (r^2)/F and take the square root.

(r²/F)·F = G·(m×M)/r²·(r²/F)

r² = G·m·M/F

r=\sqrt{\dfrac{GmM}{F}}

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A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random
Yuliya22 [10]

Answer:

b) independent samples t-test

t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154  

p_v =2*P(t_{8}>0.154) =0.881  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).  

Step-by-step explanation:

The system of hypothesis on this case are:  

Null hypothesis: \mu_1 = \mu_2  

Alternative hypothesis: \mu_1 \neq \mu_2  

Or equivalently:  

Null hypothesis: \mu_1 - \mu_2 = 0  

Alternative hypothesis: \mu_1 -\mu_2\neq 0  

Our notation on this case :  

n_1 =5 represent the sample size for group 1  

n_2 =5 represent the sample size for group 2  

We can calculate the mean and deviation for eaach group with the following formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X_1 =5.92 represent the sample mean for the group 1  

\bar X_2 =5.74 represent the sample mean for the group 2  

s_1=1.88 represent the sample standard deviation for group 1  

s_2=1.81 represent the sample standard deviation for group 2  

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:  

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}  

And now we can calculate the statistic:  

t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154  

The degrees of freedom are given by:  

df=5+5-2=8

And now we can calculate the p value using the altenative hypothesis:  

p_v =2*P(t_{8}>0.154) =0.881  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).  

7 0
4 years ago
If you need 8 oz of chocolate chips to make 1.6 lb of cookie dough how many ounces of chocolate chips will you need to make 7 lb
iren [92.7K]

Answer:

3.5 Oz of chocolate

Step-by-step explanation:

1.6 lb of cookie dough is made from chocolate of 8 Oz

1 lb will be made by 8/ 1.6 = 0.5 Oz of chocolate

Therefore

7lb of cookie dough will be made from 7 * 0.5= 3.5 Oz of chocolate/

6 0
4 years ago
The perimeter of a rectangle is 34 units. Its width is 6.5 point, 5 units.
12345 [234]
<h3><u>Question:</u></h3>

The perimeter of a rectangle is 34 units. Its width W is 6.5 units.

Write an equation to represent the perimeter in terms of the length L, and find the value of L

<h3><u>Answer:</u></h3>

The length of rectangle is 10.5 units

<h3><u>Solution:</u></h3>

Given that,

Perimeter of rectangle = 34 units

Width of rectangle = 6.5 units

Let "L" be the length of rectangle

<em><u>The perimeter of rectangle is given by formula:</u></em>

Perimeter = 2(length + width)

<em><u>Substituting the values we get,</u></em>

34 = 2(L + 6.5)

Thus the equation is found

<em><u>Solve for "L"</u></em>

L + 6.5 = \frac{34}{2}\\\\L + 6.5 = 17\\\\L = 17 - 6.5\\\\L =10.5

Thus length of rectangle is 10.5 units

6 0
3 years ago
12-3m=4+5/m <br> HELPPPP
Kipish [7]
M1= 5 , M2=1

Explanation:

12-3m-4-5/m=0
8-3m-5/m=0
(8-3m-5/m=0) * m
8m-3m^2-5=0
8m-3m^2=5
m(8-3m)=5
m1=5
m2=> (8-3m)=5
3m=3
m2= 1
6 0
3 years ago
Read 2 more answers
Determine o vértice da função quadrática y=16x²-6x-10
lord [1]
(3/16, -169/16). Creo que es correcto, tengas buenas noches
6 0
2 years ago
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