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3 years ago

12

Factor the trinomial: 2x^2+13x+21

1 answer:

steposvetlana [31]3 years ago

8 0

The answer for your answer is (x+3)(2x+7)

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Each day Alyssa jogs for 25 Minutes on the treadmill she jogs 135 Meters each day .How many kilometers will Alyssa in 25 minutes

velikii [3]

0.135
1 meter = 0.001 kilometers

4 0

3 years ago

A water storage tank has the shape of a cylinder with diameter 14 ft. It is mounted so that the circular cross-sections are vert

4vir4ik [10]

Check the picture below.

neverminding for a few seconds the volume of the cylinder, the percentage in the height used by the water will be the same as the percentage of its volume. We know the total amount or 100% of the height is 14, so what is 11 in percentage?

$\begin{array}{ccll} amount&\%\\ \cline{1-2} 14&100\\ 11&x \end{array}\implies \cfrac{14}{11}=\cfrac{100}{x}\implies 14x=1100 \\\\\\ x = \cfrac{1100}{14}\implies x = \cfrac{550}{7}\implies \boxed{x \approx 78.6}$

7 0

3 years ago

Seventy and six hundred two thousandths as a decimal number

Alex73 [517]

76.002 i think honestly don’t know but have it a try

7 0

3 years ago

Read 2 more answers

(1) Let {v1,v2,v3} be a set of vectors in Rn . If u is Span {v1,v2,v3}, show that 3u is in Span {v1,v2,v3}.

Evgesh-ka [11]

Answer:

(1)

Multiplying by 3 both sides of the equality you get that

$3u = 3c_1v_1+3c_2v_2+3c_3v_3$

3u is in the Span of the vectors $\{v_1,v_2,v_3\}$ .

(2)

That's not true, consider the following counter example.

$v_1 = (0,0,0,1)\\v_2 = (0,0,1,0)\\v_3 = (0,1,0,0)\\v_4 = (1,0,0,0)\\u = (0,1,1,1)$

$u$ is a linear combination of $v_1,v_2,v_3$ but is NOT a linear combination of $v_1,v_2,v_3,v_4.$

Step-by-step explanation:

(1)

As the hint indicates, you know that

$u = c_1 v_1 + c_2v_2+c_3v_3$

Then, if you multiply both sides of the equality by 3, you get that

$3u = 3c_1v_1+3c_2v_2+3c_3v_3$

And that's it. 3u is in the Span of the vectors $\{v_1,v_2,v_3\}$

(2)

That's not true, consider the following counter example.

$v_1 = (0,0,0,1)\\v_2 = (0,0,1,0)\\v_3 = (0,1,0,0)\\v_4 = (1,0,0,0)\\u = (0,1,1,1)$

$u$ is a linear combination of $v_1,v_2,v_3$ but is NOT a linear combination of $v_1,v_2,v_3,v_4.$

4 0

3 years ago

Help. 20 points

Alex17521 [72]

G(x)=1.58In(-)+7 is actually not the same is different but is the same because the have the x and the -

7 0

3 years ago