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gregori [183]
3 years ago
12

Factor the trinomial: 2x^2+13x+21

Mathematics
1 answer:
steposvetlana [31]3 years ago
8 0
The answer for your answer is (x+3)(2x+7)
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Which equation could be the equation of this parabola?
grin007 [14]
D, Because the equation must be in slope intercept (y=mx+b) and since it is going upwards (all positive nunbers) then the slope would be positive as well. I hope this helps!
8 0
3 years ago
Read 2 more answers
In place value the Relationship between 2,000 and 20 is how many times
Katen [24]

Answer:

100

Step-by-step explanation:

20 times 100 equals 2000

6 0
3 years ago
6 1/12= - 4 6/12 subtracting
irinina [24]

i think  that it is 2

7 0
4 years ago
F(x)=2x^2-3x+7 evaluate f(-2)
Vilka [71]

Answer:

Step-by-step explanation:

Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?

Let  p(x)=kpx+dp  and  q(x)=kqx+dq  than

f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7  

p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7  

(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)  

So you want:

−2kpk2q=0  

and

kpkq=−1  

and

2kpd2p−3kpdq+7=0  

Now I amfraid this doesn’t work as  −2kpk2q=0  that either  kp  or  kq  is zero but than their product can’t be anything but  0  not  −1 .

Answer: there are no such linear functions.

6 0
3 years ago
3) The algebraic process you use to isolate a variable in order to find what values, numbers, etc. will make an equation true. Y
vekshin1

Answer:

  You <u>solve</u> the equation.

Step-by-step explanation:

The process of finding variable values that make the equation true is called <em>solving</em> the equation.

5 0
3 years ago
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