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2 years ago

7

Evaluate each algebraic expression for given value of the variable

1 answer:

crimeas [40]2 years ago

8 0

I don't even know how to answer this I'm just extremely bored don't hate me for this but I'm just gonna go ahead and talk about me and my problem with my crush so a couple months ago I got a crush for the second time in my entire life and I'm going to marry him but he doesn't know it yet(；一_一)anyways so my friends kept pushing me into him and we r in 7th grade and he is in 8th like come on we r not in 2nd grade so I can tell he was getting annoyed and one time he even sed watch it in the quietest sweetest voice ever(ಥ﹏ಥ)so I was like Ok guys stop and they still try to push me but I don't let then but anyways I could also tell he got annoyed when I look at him so I stopped and now he the one looking and me and he started to walk rly close to me to and wherever I go I always see him I'm so happy. (ಥ﹏ಥ)so ya and then I finally gathered up the courage to follow him on instagram and my friends are telling me to dm him but idk if I want to... mabey I should just let him come to me idk but ya that's what's happening baiiiiii.(´・ω・`)

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Need help asappppppp

Reika [66]

Answer:

press control u on ur google forms quiz than scroll all the way down to the questions and the answer should be right next to them.

4 0

2 years ago

Joan earns $9.25 per hour. She worked 37.6 hours last week. What was the amount of her check?

slava [35]

37.6*9.25=$<span>347.8 without deductions</span>

3 0

2 years ago

Read 2 more answers

A 3mL unit dose of levalbuterol HCl contains 0.63mg of active ingredient. If 2 unit doses are used, how many mg of active ingred

Sergio039 [100]

Answer: 0.42 mg

Step-by-step explanation:

Given : A 3mL unit dose of levalbuterol HCl contains 0.63mg of active ingredient.

Then , the amount of active ingredient in 1 ml dose of levalbuterol HCl = $\dfrac{0.63}{3}$

$=\dfrac{63}{300}=\dfrac{21}{100}=0.21\ mg$

Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl will be :-

$2\times0.21=0.42\ mg$

Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl =0.42 mg

6 0

3 years ago

John has a boat that will travel at the rate of 15 kph in still water. He can go upstream for 35 km in the same time it takes to

Otrada [13]

Answer:

The boat traveling at 24 kph when John goes downstream.

Step-by-step explanation:

We are given the following in the question:

John has a boat that will travel at the rate of 15 kph in still water.

Let x be the speed of the current.

Speed of boat in upstream

$(15-x)\text{ kph}$

Speed of water in downstream

$(15+x)\text{ kph}$

Relation:

$\text{Speed} = \dfrac{\text{Distance}}{\text{Time}}$

We have to find the speed of boat in downstream.

Time to travel upstream for 35 km = Time to travel 140 km downstream

$\displaystyle\frac{35}{15-x}=\frac{140}{15+x}\\\\35(15+x) = 140(15-x)\\525 + 35x = 2100 - 140x\\175x = 1575\\x = 9$

Thus, speed of current is 9 kph.

Speed of boat in downstream = 15 + 9 = 24 kph.

Thus, the boat traveling at 24 kph when John goes downstream.

4 0

3 years ago

In two or more complete sentences describe how to determine the appropriate model for the set of data. (1, 1), (3, 2), (6, 3), (

Dafna1 [17]

Answer:

3,2

Step-by-step explanation:

hope you like it then comment

5 0

2 years ago