Find all sets of three consecutive positive even integers with a sum no greater than 36

The area of a circular place is 45 square inches.estimate the radius to the nearest integer

geniusboy [140]

A = π*r^2
r = √(A/π) = √(45/π) ≈ 3.78

The radius is approximately 4 inches.

7 0

3 years ago

An advertising company is designing a new logo that consists of a shaded triangle inside a parallelogram.What is the area, in sq

tatyana61 [14]

<h2>Explanation:</h2><h2 />

The complete question is shown in the figure below. As you can see one square units is well shown in the graph. So we can conclude that the distance between two consecutive points is 1 unit. If so, then we can calculate the area of the parallelogram as follows:

$A=b\times h \\ \\ A:Area \\ \\ b:Base \\ \\ h:Height \\ \\ \\ CB=b \\ \\ AB=h$

Then, finding CB by Pythagorean Theorem:

$CB=\sqrt{6^2+4^2} \\ \\ CB=2\sqrt{13}$

And:

$AB=4$

Therefore:

$A=(2\sqrt{13})(4) \\ \\ \boxed{A=8\sqrt{13} \ units^2}$

6 0

3 years ago

Help geometry what I m jlf <br> Picture provided

Zolol [24]

Answer:

$\angle\,JLF = 114^o$ which agrees with option"B" of the possible answers listed

Step-by-step explanation:

Notice that in order to solve this problem (find angle JLF) , we need to find the value of the angle defined by JLG and subtract it from $180^o$ , since they are supplementary angles. So we focus on such, and start by drawing the radii that connects the center of the circle (point "O") to points G and H, in order to observe the central angles that are given to us as $90^o$ and $138^o$ . (see attached image)

We put our efforts into solving the right angle triangle denoted with green borders.

Notice as well, that the triangle JOH that is formed with the two radii and the segment that joins point J to point G, is an isosceles triangle, and therefore the two angles opposite to these equal radius sides, must be equal. We see that angle JOH can be calculated by : $360^o-90^o-138^o=132^o$