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Ymorist [56]
2 years ago
7

Evaluate the integral i. i = int_0^(pi/2) ( 3 (sin(t))^2 cos(t)i + 6 sin(t)(cos(t))^5j + 4 sin(t)cos(t)k )dt

Mathematics
1 answer:
marishachu [46]2 years ago
3 0
See, please, the suggested option.
If it possible, check it in other sources.

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10) Thirty-seven percent of the American population has blood type O+. What is the probability that at least four of the next fi
lisabon 2012 [21]

Answer:

0.06597

Step-by-step explanation:

Given that thirty-seven percent of the American population has blood type O+

Five Americans are tested for blood group.

Assuming these five Americans are not related, we can say that each person is independent of the other to have O+ blood group.

Also probability of any one having this blood group = p = 0.37

So X no of Americans out of five who were having this blood group is binomial with p =0.37 and n =5

Required probability

=The probability that at least four of the next five Americans tested will have blood type O+

= P(X\geq 4)\\= P(X=4)+P(x=5)\\= 5C4 (0.37)^4 (1-0.37) + 5C5 (0.37)^5\\= 0.06597

7 0
3 years ago
Read 2 more answers
Evaluate -125^(-1/3)
soldi70 [24.7K]

Answer:

1/-125^(1/3)

=1/-5

=-0.2

3 0
3 years ago
Mrs. Connors went to the shopping mall and spent 3/5 of the money she had in her wallet at the department store. She bought new
Katen [24]
She spent 115 dollars on the pots and pans
7 0
3 years ago
Help with this proof
mixer [17]
Essentially, what we need to do here is prove that BE=EC, BE=CB, and.or CE=BC therefore making it isosceles. With ∠AEC=∠DEB, we know AE=DE, so EC=EB (the points go in order). Therefore, as EC=EB, BEC is isosceles (it has at least 2 equal sides).

Feel free to ask further questions! 
7 0
2 years ago
Write the equation for a parabola with a focus at (6,-4) and a directrix at y= -7
shtirl [24]

Given:

The focus of the parabola is at (6,-4).

Directrix at y=-7.

To find:

The equation of the parabola.

Solution:

The general equation of a parabola is:

y=\dfrac{1}{4p}(x-h)^2+k                  ...(i)

Where, (h,k) is vertex, (h,k+p) is the focus and y=k-p is the directrix.

The focus of the parabola is at (6,-4).

(h,k+p)=(6,-4)

On comparing both sides, we get

h=6

k+p=-4                            ...(ii)

Directrix at y=-7. So,

k-p=-7                            ...(iii)

Adding (ii) and (iii), we get

2k=-11

k=\dfrac{-11}{2}

k=-5.5

Putting k=-5.5 in (ii), we get

-5.5+p=-4

p=-4+5.5

p=1.5

Putting h=6, k=-5.5,p=1.5 in (i), we get

y=\dfrac{1}{4(1.5)}(x-6)^2+(-5.5)

y=\dfrac{1}{6}(x-6)^2-5.5

Therefore, the equation of the parabola is y=\dfrac{1}{6}(x-6)^2-5.5.

4 0
2 years ago
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