Evaluate the integral i. i = int_0^(pi/2) ( 3 (sin(t))^2 cos(t)i + 6 sin(t)(cos(t))^5j + 4 sin(t)cos(t)k )dt

pantera1 [17]

We want to get rid of the stuff in the denomenator

gcd of the denomenator is 2x
but wait, we can get rid of the deonmenator in the numerator by multiplying by 4x

muliplty the whole thing by 4x/4x

we get $\frac{x(x^2)}{4(2)+2(x+4)}=\frac{x^3}{2x+16}$

3 0

3 years ago

Give an actual answer please

noname [10]

Hello There!!

Your best answer choice will be is A.

(2x + 7) feet.

Because, All you have to do for this problem is factor the equation. I would be hard to explain on this so I recomment you watch a video on it. If you did not know how to factor, you could have muliplied each of the answers by themselves to determine the correct answer because it is a square.

Hope This Helps!!

4 0

3 years ago

Read 2 more answers

Name the property of equality that justifies: (I have to put question into an equation below because I can't get it in this ques

Rainbow [258]

The best and most correct answer among the choices provided by your question is the third choice or letter C "<span>Multiplication Property of Equality"</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

7 0

3 years ago

The Town of Hertfordshire clerk knows that 23% of dogs in the town have completed emotional support training. Hertfordshire plan

Nataly_w [17]

Answer:

95.64% probability that under 30% of the dogs are emotional support trained

Step-by-step explanation:

For each dog, there are only two possible outcomes. Either they have completed emotional support training, or they have not. So we use the binomial probability distribution to solve this problem.

However, we are working with samples that are considerably big. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .