The answer is x = 10, y = 10.
Step 1: rearrange the second equation for y.
Step 2: substitute y from the second equation into the first equation.
Step 3. Calculate y.
Step 1.
<span>The second equation is: 6x + 3y = 90
Divide both sides of the equation by 3:
(6x + 3y)/3 = 90/3
6x/3 + 3y/3 = 30
2x + y = 30
Rearrange the equation:
y = 30 - 2x
Step 2.
</span>Substitute y from the second equation (y = 30 - 2x) into the first equation:
<span>15x + 9y = 240
15x + 9(30 - 2x) = 240
15x + 270 - 18x = 240
15x - 18x = 240 - 270
-3x = -30
x = -30/-3
x = 10
Step 3.
Since </span>y = 30 - 2x and x = 10, then:
y = 30 - 2 * 10
y = 30 - 20
y = 10
Answer:
A
Step-by-step explanation:
Since cosine is positive and sine is negative that puts θ in Quad IV.
From right triangles we know:
Cos θ = adjacent/hypotenuse = 5/13
sin θ = opposite/hypotenuse = ?/13
To find the opposite side across from θ use the pythagorean theorem.
5² + y² = 13²
25 + y² = 169
y² = 144
y = 12
we are given that sin is < 0 so sinθ = -12/13
Answer:
look at the picture i have sent
Answer:
Step-by-step explanation:
The answer is the 1st, 2nd and last one
