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alekssr [168]
3 years ago
6

Line go passes through points (2,5) and (6,9) which equation represents line gh

Mathematics
1 answer:
irina [24]3 years ago
5 0
Make an equation in point-slope form, which is y - y = m(x - x)

First find the slope. The formula for slope is (y - y) over (x - x). In this case, the slope is (9 - 5) over (6 - 2) which simplifies to 1. The slope will be m in the point-slope equation.

Now fill in the formula:
9 - 5 = 1 (6-2)

This is the answer.
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Please help with these problems! Will mark answer as brainliest and give 30 points. You have to show your work for each problem.
gulaghasi [49]

Answer:

1) (2x + 2)(x + 2)

2)  2(x + 1)(x - 1)

3) (x^2 + 3)(x^2 - 3)

4) 2x(x + 5)(x - 2)

5) (5x + 2y)(5x - 2y)

Step-by-step explanation:

1)

2x^2 + 6x + 4

= 2x^2 + 4x + 2x + 4

= 2x(x + 2) + 2(x + 2)

= (2x + 2)(x + 2)

2)

2x^2 - 2

= 2(x^ 2 - 1) (The difference of two squares)

= 2(x + 1)(x - 1)

3)

x^4 - 9 (The difference of two squares)

=(x^2 + 3)(x^2 - 3)

4)

2x^3 + 6x^2 - 20x

= 2x(x^2 + 3x - 10)

= 2x(x + 5)(x - 2)

5)

25x^2 - 4y^2         (The difference of two squares)

= (5x + 2y)(5x - 2y)

4 0
3 years ago
Contestant and like terms. What do they mean?
ICE Princess25 [194]

Answer:

Step-by-step explanation:

Like Terms: terms that have the same variable raised to the same power. So like 5x plus 5x plus 5. 5x and 5x are like terms.

I'm going to assume you mean Constant instead of contestant so

Constant: Terms without variables

Example: 5x+2x+7

5x and 2x are like terms

7 is a Constant

8 0
3 years ago
Need help to solve 7/6r = -1/2
fredd [130]

Answer:

r = -3/7.

Step-by-step explanation:

To solve this equation, we multiply both sides by 6/7. This is the reciprocal of the coefficient in r (7/6) and will "cancel out" the expression. So:

-1/2 x 6/7 = -6/14 = -3/7.

As such, r = -3/7.

I hope this helps!

3 0
3 years ago
Read 2 more answers
Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if
Delicious77 [7]

Answer:

(1)Equivalence Relation

(2)Not Transitive, (0,3) is missing

(3)Equivalence Relation

(4)Not symmetric and Not Transitive, (2,1) is not in the set

Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

  • Reflexivity: If \forall x \in A, x \rightarrow x
  • Symmetry: \forall x,y \in A, $if x \rightarrow y,$ then y \rightarrow x
  • Transitivity: \forall x,y,z \in A, $if x \rightarrow y,$ and y \rightarrow z, $ then x \rightarrow z

(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

5 0
3 years ago
4 2/5 divided by 3 1/7 euals plz give mixed number answer ty
antoniya [11.8K]
4 2/5 = 22/5
3 1/7 = 22/7
22/5 x 7/22 = 154/110 = 7/5

The answer is 1 2/5
8 0
3 years ago
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