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mars1129 [50]
4 years ago
11

PLZZ HELP ME If there are 14 green Skittles, how many yellow ones are there?

Mathematics
1 answer:
gulaghasi [49]4 years ago
3 0
<span>Let's look at the information that you do have.
y = yellow
g = green

g + y = 38
</span><span>g = 38 - y

If there are 14 green skittles,then we know that:
</span>14 + y = 38
14 = 38 - y<span>
so, we can then do the equation:
38 - 14 = y
38 - 14 = 24
y = 24
</span>
So, the answer is 24 green skittles.
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Answer:

5cm wide, 10cm long.

Step-by-step explanation:

I came to this answer by looking for common factors between 50 and 5, and I found 10.

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Jean works for the government and was conducting a survey to determine the income levels of a number of different neighborhoods
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Answer:

0.0418 = 4.18% probability that the average income level in the neighborhoods was less than $38,000.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Jean knows that the mean income level in the country is $40,000, with a standard deviation of $2,000.

This means that \mu = 40000, \sigma = 2000

Jean selected three neighborhoods and determined the average income level.

This means that n = 3, s = \frac{2000}{\sqrt{3}} = 1154.7

What is the probability that the average income level in the neighborhoods was less than $38,000

This is the pvalue of Z when X = 38000. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{38000 - 40000}{1154.7}

Z = -1.73

Z = -1.73 has a pvalue of 0.0418

0.0418 = 4.18% probability that the average income level in the neighborhoods was less than $38,000.

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Step-by-step explanation:

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