n, n + 2, n + 4 - three consecutive even integers
the twice the sum of the second and third: 2[(n + 2) + (n + 4)]
twelve less than six times the first: 6n - 12
The equation:
2[(n + 2) + (n + 4)] = 6n - 12
2(n + 2 + n + 4) = 6n - 12
2(2n + 6) = 6n - 12 <em>use distributive property</em>
(2)(2n) + (2)(6) = 6n - 12
4n + 12 = 6n - 12 <em>subtract 12 from both sides</em>
4n = 6n - 24 <em>subtract 6n from both sides</em>
-2n = -24 <em>divide both sides by (-2)</em>
n = 12
n + 2 = 12 + 2 = 14
n + 4 = 12 + 4 = 16
<h3>Answer: 12, 14, 16</h3>
Answer:
D
Step-by-step explanation:
We need the numbers of each before we can calculate the probability
Number of even numbers are 50
Number of odd numbers are 50
Number of perfect squares;
1 , 4 , 9 , 16 , 25 , 36 , 49 , 64 , 81 and 100
10 perfect squares
Probability of selecting even = probability of selecting odd = 50/100 = 1/2
Probability of selecting a perfect square = 10/100 = 1/10
Thus, the probability of having the draws in the other stated in the question will be;
1/2 * 1/2 * 1/10 = 1/40
Answer:
(3 * 2.50 + 8 * 1.25) d =
3*2.50 d + 8*1.25 d
or
7.50 d + 10 d
Not all of the student body would have responded therefore her conclusion was incorrect, could be changed to be right by saying 90% of people who responded to a survey said the school colours should be changed.
