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2 years ago

Expand and simplify (2x+5y) (x-3y)

1 answer:

3 0

Should be simple:

Let's take this one at a time.

2x(x-3y)

You'd get:
$2x^2-3xy$
for the first one.

2nd one:
5y(x-3y)
you'd get:
$+5xy-3y^2$

Put them both together:
$2x^2-3xy+5xy-3y^2$

Combine like terms.

Your Answer:
$2x^2+2xy-3y^2$

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Given that 6x – 5y = 14 Find x when y = 2

Sloan [31]

Answer:

x = 4

Step-by-step explanation:

Given

6x - 5y = 14 ← substitute y = 2 into the equation

6x - 5(2) = 14

6x - 10 = 14 ( add 10 to both sides )

6x = 24 ( divide both sides by 6 )

x = 4

4 0

2 years ago

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A blank is a rectangular

UNO [17]

Answer:

I would say parallelogram. So the rectangle still fits but more shapes can be applied.

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3 years ago

Evaluate the expression for the given variable values. 3∣m+2n∣2−(mn)2 if m=3 and n=−5

Ira Lisetskai [31]

From my thinking don’t use this one because I’m not really answering 5-2=3=3

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2 years ago

Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)

JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

Solution:

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)$ is given by:

$\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9$

Plugging in the values in formula, we get,

$\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}$

Hence, the midpoint of the segment is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

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2 years ago

The probability???????????????

slamgirl [31]

Answer:12/87

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2 years ago