Given:
<span>(Isosceles Trianlge) ----∆ABC Perimeter = 50 meters
</span><span>(Right Triangle) ---------∆ABD Perimeter = 40 meters
</span><span>Segment BD bisects segment AC into two equal lenghts
Required: BD
Solution:
We know that isosceles triangle has two equal legs and a base. Therefore,
For </span>∆ABC,
AB & BC are the two equal legs.
AC is the base.
For right triangle ∆ABD,
AB is the hypotenuse
AD is the base leg
BD is the other leg
Let us represent segments AB & BC as a
segment AC as b
segment BD as h
segment AD as b/2
In equation we have,
∆ABC Perimeter = a + a + b
50 = 2a + b eq. (1)
∆ABD Perimeter = a + b/2 + h
40 = a + b/2 + h eq. (2)
Dividing eq. (1) by 2, we get
25 = a + b/2 eq. (3)
Substitute eq. (3) in eq. (2),
40 = (25) + h
h = 15 meters
<em> ANSWER: BD = 15 meters</em>
Answer:
Step-by-step explanation:
Given
Required
The diameter
The volume of a cylinder is:
So, we have:
Divide both sides by the common factors
Take square roots of both sides
The diameter is:
So:
or
The second one. All the other ones have degree 6.
Answer:
C
Step-by-step explanation:
(8×4x) - (8×12) + 9x
32x - 96 + 9x
41x -96