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borishaifa [10]
4 years ago
9

Carlos is spreading mulch in a circle on top of an area where he has planted some seeds. He has enough mulch to cover an area th

at is 12.5 square feet. How much rubber edging does Carlos need to encircle the mulch that will cover the seeds?
Mathematics
1 answer:
ioda4 years ago
7 0
<span>We are working with a circle, which means that our rubber edging needs to be as long as the circumference of the circle. Circumference (C) is calculated by multiplying the diameter (d) times pi (Ď€). [C=dĎ€] And the diameter is simply the radius (r) multiplied by two. [d=2r] We can calculate the radius by dividing 12.5 by pi and then taking the square root of the quotient.[r=âš(12.5/Ď€)] In this case, the radius is equal to 1.99. We then double the radius and multiply by pi.[C=2(1.99)Ď€] When we do, we find that the circumference is 12.5. Therefore, Carlos will need to buy 12.5 feet of rubber edging.</span>
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kati45 [8]

Answer:

The length of the shortest piece is 1\textrm{ ft}.

The length of the medium-sized piece is 3\textrm{ ft}.

The length of the longest piece is 7\textrm{ ft}.

Step-by-step explanation:

The five-step method is GUESS method.

Given:

Length of copper wire, L=11\textrm{ ft}

Length of longest piece is 6 feet longer than the shortest one.

Length of the medium-sized piece is 3 times the shortest one.

Unknown:

Length of longest, medium-sized and shortest pieces of wire.

Let the length of shortest piece be x feet.

Therefore, the length of longest piece is equal to 6+x.

And, length of the medium-sized piece is equal to 3x.

Evaluate:

Sum of lengths of longest, medium-sized and shortest pieces of wire is equal to the total length of wire. So,

6+x+x+3x=11\\5x+6=11\\5x=11-6\\5x=5\\x=\frac{5}{5}=1

Substitute and Solve:

Now, we have, x=1.

Substitute 1 for x and solve for each sizes of wire pieces. This gives,

Length of shortest piece = x=1\textrm{ ft}

Length of medium-sized piece = 3x=3(1)=3\textrm{ ft}

Length of longest piece = 6+x=6+1=7\textrm{ ft}

Therefore, the lengths of shortest, medium-sized, and longest pieces are 1\textrm{ ft}, 3\textrm{ ft} and 7\textrm{ ft} respectively.

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Answer:

Step-by-step explanation:

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Now we substitute the value of k from eq2 into eq1.

 

x2 + x(3 - 2x) - 3x + 4 = 0

 

 

Solve for x from this equation.  Then plug in the value of x into eq2 to solve for k

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