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3 years ago

Simplify the expression: (-4 + v)(3) - =

Mathematics

1 answer:

lara31 [8.8K]3 years ago

3 0

Answer:

-12 + 3v Is the answer

Hope this helps :)

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You are buying a $50 video game as a holiday gift for your brother luckily you have not just one but two coupons for that store

postnew [5]

Whats the question though?

6 0

4 years ago

F(x) = x2 + 3x + 5? how do you slove this

hoa [83]

Answer:

it equal 3+3+0+123393.8393

Step-by-step explanation:

5 0

4 years ago

7. a hockey arena has 10 920 seats. the first row of seats around the rink has 220 seats. the number of seats in each subsequent

Mazyrski [523]

The number of rows in the arena is 26

<h3>How to determine the number of rows?</h3>

The hockey arena illustrates an arithmetic sequence, and it has the following parameters:

First term, a = 220
Sum of terms, Sn = 10920
Common difference, d = 16

The number of rows (i.e. the number of terms) is calculated using:

$S_n = \frac{n}{2}(2a + (n -1) * d)$

So,we have:

$10920 = \frac{n}{2}(2 * 220 + (n -1) * 16)$

Evaluate the terms and factors

$21840 = n(440 + 16n -16)$

Evaluate the like terms

21840 = n(424+ 16n)

Expand

21840 = 424n + 16n^2

Rewrite as:

16n^2 + 424n - 21840 = 0

Using a graphical tool, we have:

n = 26

Hence, the number of rows in the arena is 26

Read more about arithmetic sequence at:

brainly.com/question/6561461

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4 0

2 years ago

Select the functions that have a value of 0.

Sphinxa [80]

Answer:

Step-by-step explanation:

$k\in\mathbb{Z}\\\\\sin x=0\iff x=180^ok\\\\\cos x=0\iff x=90^o+180^ok\\\\\tan x=0\iff x=180^ok\\\\\cot x=0\iff x=90^o+180^ok\\\\\csc x\neq0\ \text{for}\ x\in\mathbb{R}-\{180^ok\}\\========================\\\\\sin270^o\neq0\\\\\cos90^o=\cos(90^o+180^o\cdot0)=0\\\\\tan0^o=\tan(180^o\cdot0)=0\\\\\csc(-180^o)\neq0\\\\\cos(-90^o)=\cos(90^o-180^o)=\cos(90^o+180^o\cdot(-1))=0\\\\\cot270^o=\cot(90^o+180^o)=0$

3 0

3 years ago

Through :(4,2),parallel to y =-3/4x-5<br> Solve for y

alex41 [277]

Answer:

y = $\frac{ - 3}{4}$ x + 5

Step-by-step explanation:

The Line equation is:

y = $\frac{- 3}{4} x - 5$

The line equation is in the form of y = m x + c

Slop of this line is (m1) = $\frac{ - 3}{4}$

Let another line with slop (m2) , passes through point (4 , 2)

As per question the another line is parallel to the given line equation

So, slop of both the lines are equal

∴ (m2) = (m1) = $\frac{ - 3}{4}$

Hence equation of another line with slop $\frac{ - 3}{4}$ and passing through points ( 4 , 2) is

y - y1 = (m2) (y - x1)

I.e y - 2 = $\frac{ - 3}{4}$ (x - 4)

Or, $4\times (y -2) = (- 3)\times (x - 4)$

Or , 4y - 8 = -3x + 12

Or, 4y = -3x + 12 + 8

Or , 4y = -3x + 20

∴ y = $\frac{ - 3}{4}$ x + 5

Hence The value of y = $\frac{ - 3}{4}$ x + 5 Answer

6 0

4 years ago