26-18=8. 8/18=4/9=44.444 (repeating)%
Answer:
<em>129 </em>
Step-by-step explanation:
Increasing rate of length, 
= 9 cm/s
Increasing rate of width, 
= 7 cm/s
Length, l = 12 cm
Width, w = 5 cm
To find:
Rate of increase of area of rectangle at above given points.
Solution:
Formula for area of a rectangle is given as:
OR
Differentiating w.r.to t:
Putting the values:
Answer:
9.5 m
Step-by-step explanation:
If width is -- x
12.4 + x + 12.4 + x = 43.8
2x = 19
x = (19/2)
x = 9.5 m
Thenks and mark me brainliest :))
Answer:
100.75 liters
Step-by-step explanation:
Data provided in the question:
t (min) 0 0.5 1 1.5 2 2.5 3
r (l/min) 44 40 37 34 30 27 23
Now,
left endpoint approximation
= 0.5 × ( 44 + 40 + 37 + 34 + 30 + 27 )
= 0.5 × 212
= 106
Right endpoint approximation
= 0.5 × ( 40 + 37 + 34 + 30 + 27 + 23 )
= 0.5 × 191
= 95.5
Therefore,
the average of the left- and right-endpoint approximations
= [ 106 + 95.5 ] ÷ 2
= 100.75 liters
the first rate is 1.25 ur on your own for the rest
