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3 years ago

What is one tenth of 0.5

Mathematics

1 answer:

Paraphin [41]3 years ago

8 0

0.5 x 1/10 = 0.05 All you do is multiply

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True or False: The null hypothesis should be rejected at a 10% level of significance when testing whether age has any effect on

olga_2 [115]

Answer:

False

Step-by-step explanation:

The null hypothesis is rejected or accepted on the basis of level of significance. When the p-value is greater than level of significance we fail to reject the null hypothesis and null hypothesis is then accepted. It is not necessary that all null hypothesis will be rejected at 10% level of significance. To determine the criteria for accepting or rejecting a null hypothesis we should also consider p-value.

7 0

3 years ago

Can someone plz help me out

Shkiper50 [21]

2.false. This is so as 3 to 4 or 3/4=0.75 while 4 to 3 is 1.333333333333333 infinite.

7 0

4 years ago

Where do u put parentheses yo make the equation 10+9×3-1×2 true?

myrzilka [38]

Answer

((10+9)x3-1)x2

=(19x3-1)x2

=(57-1)x2

=56x2=112

5 0

3 years ago

A bakery recorded the number of muffins and bagels it sold for a seven day period. For the data presented, what does the value o

atroni [7]

Answer:

Mean of bagel

Step-by-step explanation:

Working out each of the statically summaries Given in the option :

Mean of muffin :

Mean = Σx / n

n = sample size

(61 + 20 + 32 + 58 + 62 + 61 + 56) / 7

= 350 / 7

= 50

Mean of bagel :

Mean = Σx / n

n = sample size

(34 + 45 + 43 + 42 + 46 + 72 + 75) / 7

= 357 / 7

= 51

Hence, from the result obtained, we could see that the value of 51 summarizes the mean of bagel.

3 0

3 years ago

The joint probability mass function of XX and YY is given by p(1,1)=0p(2,1)=0.1p(3,1)=0.05p(1,2)=0.05p(2,2)=0.3p(3,2)=0.1p(1,3)=

inessss [21]

Answer:

P(Y=1|X=3)=0.125

Step-by-step explanation:

Given :

p(1,1)=0

p(2,1)=0.1

p(3,1)=0.05

p(1,2)=0.05

p(2,2)=0.3

p(3,2)=0.1

p(1,3)=0.05

p(2,3)=0.1

p(3,3)=0.25

Now we are supposed to find the conditional mass function of Y given X=3 : P(Y=1|X=3)

P(X=3) = P(X=3,Y=1)+P(X=3,Y=2) +P(X=3,Y=3)

P(X=3)=p(3,1) +p(3,2) +p(3,3)

P(X=3)=0.05+0.1+0.25=0.4

$P(Y=1|X=3)=\frac{P(X=3,Y=1)}{P(X=3)} =\frac{p(3,1)}{P(X=3)}=\frac{0.05}{0.4}= 0.125$

Hence P(Y=1|X=3)=0.125

8 0

3 years ago