Hello, 1) 100=20*5999=199*5+4Number of multiple of 5 =(199-20+1)=180 2)100=15*7-5999=142*7+5Number of multiple of 7= 142-15+1=128 3)5*7=35100=3*35-5999=28*35+19Number of multiple of (5 and 7) =28-3+1=26 4) Number of three-digit numbers= 999-100+1=900 5)Number of three-digit numbers are multiples of neither 5 nor 7=900-(128+180-26)=618 Proof :This programm in QB64 print nb=618.
' How many three-digit numbers are multiples of neither 5 nor 7? DIM i AS INTEGER, nb AS INTEGER nb = 0 FOR i = 100 TO 999 IF i MOD 5 = 0 OR i MOD 7 = 0 THEN ELSE nb = nb + 1 PRINT nb; i END IF