Answer:
To solve a system of linear equations graphically we graph both equations in the same coordinate system. The solution to the system will be in the point where the two lines intersect. The two lines intersect in (-3, -4) which is the solution to this system of equations. I hope this helped!
Answer:
x=2
Step-by-step explanation:
Simplify both sides of the equation.
2x−1−(−x + 3)=6−2x
(Distribute the Negative Sign)
2x−1 + −1(−x + 3)=6−2x
2x + −1 + −1(−x) + (−1)(3)=6−2x
2x + −1 + x + −3=6−2x
2x + −1 + x + −3=6 + −2x
(Combine Like Terms)
(2x + x) + (−1 + −3)=−2x+6
3x + −4=−2x + 6
3x−4=−2x + 6
Add 2x to both sides.
3x−4 + 2x=−2x + 6 + 2x
5x−4=6
Add 4 to both sides.
5x−4 + 4=6 + 4
5x=10
Divide both sides by 5.
5x/5=10/5
x=2
1 liter is equal to 1000 milliliters, so we can multiply 200 liters by 1000 to get 200000 milliliters, which should be your answer. In general, the "milli-" prefix denotes a factor of one thousand times smaller, so 1 meter is equal to 1000 millimeters, 1 second is equal to 1000 milliseconds, and so on.
56392 rounded to the nearest ten thousand is 60,000
Answer:
a. 7/22
b. 28/33
c. 7/22
d. dependent events
Step-by-step explanation:
The total number of cards is given as 7 + 5 = 12.
The probability if a card being green on the first pick, P(G) = 7/12
The probability of a card being yellow on the first pick, P(Y) = 5/12
Because there is no replacement, the card are going to be short by one card. Therefore, the second pick will be like this:
P(GG) = ( 7/12×6/11)
P(GY) = ( 7/12 × 5/11)
P(YG) = ( 5/12×7/11)
P(RR) = ( 5/12 ×4/11)
a. P (G1 and G2) = ( 7/12×6/11)
= 7/22
b. P( At least one is green) = ( 7/12×6/11) + ( 7/12 × 5/11) + ( 5/12×7/11)
= 28/33
c. P(G2G1) = 7/22
d. the events are dependent. They do not give the same result.