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3 years ago

WILL MARK BRAINLIEST PLEASE HELP! How many three-digit numbers are multiples of neither 5 nor 7?

Mathematics

2 answers:

Temka [501]3 years ago

7 0

Best Answer

999/7 is just over 142

100/7 is just over 14

so there are (142 - 14) = 128 numbers that are multiples of 7, hence there are 999-99-128 = 772 numbers that are not multiples of 7.

Salsk061 [2.6K]3 years ago

5 0

Hello,
1)
100=20*5999=199*5+4Number of multiple of 5 =(199-20+1)=180
2)100=15*7-5999=142*7+5Number of multiple of 7= 142-15+1=128
3)5*7=35100=3*35-5999=28*35+19Number of multiple of (5 and 7) =28-3+1=26
4) Number of three-digit numbers= 999-100+1=900
5)Number of three-digit numbers are multiples of neither 5 nor 7=900-(128+180-26)=618
Proof :This programm in QB64 print nb=618.

' How many three-digit numbers are multiples of neither 5 nor 7?
DIM i AS INTEGER, nb AS INTEGER
nb = 0
FOR i = 100 TO 999
    IF i MOD 5 = 0 OR i MOD 7 = 0 THEN
    ELSE
        nb = nb + 1
        PRINT nb; i
    END IF

NEXT i
PRINT "nb="; nb
END

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The terminal side of θ in standard position contains the point (–4, 3). Find the exact values of the six trigonometric functions

Morgarella [4.7K]

Answer:

When we have a rectangular point (x, y), the angle between the x-axis and a ray that connects the origin with this point is given by:

Tan(θ) = y/x.

Cos(θ) = x/(√(x^2 + y^2))

Sin(θ) = y/(√(x^2 + y^2))

So for the point (-4,3) we have:

x = -4

y = 3

√( (-4)^2 + 3^2) = √(16 + 9) = √25 = 5

Then:

Tan(θ) = 3/-4 = -(3/4)

Sin(θ) = 3/5

Cos(θ) = -4/5

And for the other 3 trigonometric functions (the inverses of the 3 above ones) we have:

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3 years ago

Sam, Jimmy, and Andre shared a number of pennies in the ratio 8:5:3. Sam and Andre received a

ddd [48]

Jimmy received 122 pennies more than Andre

Solution:

Given that , Sam, Jimmy, and Andre shared a number of pennies in the ratio 8:5:3

Sam and Andre received a total of 671 pennies.

Now, let the H.C.F of number of pennies with them be "x"

Then, number of pennies with Sam will be 8x

Number of pennies with Jimmy will be 5x

Number of pennies with Andre will be 3x

Now, we know that, Sam and Andre has a total of 671 pennies

$\begin{array}{l}{\Rightarrow \quad 8 x+3 x=671} \\\\ {\Rightarrow \quad 11 x=671} \\\\ {\Rightarrow \quad x=61}\end{array}$

$\begin{array}{l}{\text { Then, Sam will have } 8 \times 61=488 \text { pennies, }} \\\\ {\text { Jimmy will have } 5 \times 61=305 \text { pennies, }} \\\\ {\text { Andre will have } 3 \times 61=183 \text { pennies. }}\end{array}$

Calculating how many more pennies Jimmy received than Andre:

Number of Pennies Jimmy received more than Andre = Pennies with jimmy - Pennies with Andre

= 305 – 183 = 122

Hence, jimmy has 122 pennies more than Andre

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3 years ago

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Klio2033 [76]

A0 = 7 because 2 * 5 * 7 = 70

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4 years ago

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Paha777 [63]

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answer
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