A toy car launched into the air has a height (h feet) at any given time (t second) as h= -16t + 160t until it hits the ground. A
t what times is it at a height of 9 feet above the ground?
2 answers:
Answer:
and ![t_{2} \approx 0.057\,s](https://tex.z-dn.net/?f=t_%7B2%7D%20%5Capprox%200.057%5C%2Cs)
Step-by-step explanation:
The following polynomial is needed to be solved:
![-16\cdot t^{2} + 160\cdot t - 9 = 0](https://tex.z-dn.net/?f=-16%5Ccdot%20t%5E%7B2%7D%20%2B%20160%5Ccdot%20t%20-%209%20%3D%200)
The roots are found by means of the General Equation for Second-Order Polynomials:
and ![t_{2} \approx 0.057\,s](https://tex.z-dn.net/?f=t_%7B2%7D%20%5Capprox%200.057%5C%2Cs)
Physically speaking, both solutions are reasonable.
Answer:
t = 0.0625
Step-by-step explanation:
Given that,
Height, h = -16t + 160t
To obtain time,t at height,h = 9feet
We substitute h = 9 into the given equation to have:
9 = - 16t + 160t
: 9 = 144t
t = 9/ 144 = 0.0625
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Step-by-step explanation: