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3 years ago

One is the additive identify true or false

Mathematics

1 answer:

Maurinko [17]3 years ago

5 0

Whats the question i dont think u stated it

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4 / 7 * 2 / 3 * *9/16

lara31 [8.8K]

$\bf \cfrac{4}{7}\cdot \cfrac{2}{3}\cdot \cfrac{9}{16}\implies \cfrac{4}{16}\cdot \cfrac{9}{3}\cdot \cfrac{2}{7}\implies \cfrac{1}{4}\cdot \cfrac{3}{1}\cdot \cfrac{2}{7}\implies \cfrac{1}{7}\cdot \cfrac{3}{1}\cdot \cfrac{2}{4}\implies \cfrac{1}{7}\cdot \cfrac{3}{1}\cdot \cfrac{1}{2}\\\\\\\cfrac{1\cdot 3\cdot 1}{7\cdot 1\cdot 2}\implies \cfrac{3}{14}$

4 0

3 years ago

The baker at weis supermarket will cut 5 indeticial loaves of bread into pices that are 1/3 . After he cuts the 5 loaves how man

IrinaK [193]

Answer:

15 pieces

Step-by-step explanation:

we see if we get 3 pieces from one bread then 5 will be 15

hope it helps you

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5 0

3 years ago

Read 2 more answers

The volume of a metal cylindrical rod is 126 cubic meters. The radius is 6 m. What is the height of the rod in millimeters?

Dahasolnce [82]

Answer:

1.11 mm

Step-by-step explanation:

The height of a cylinder can be found using the formula: h=V/(πr^2)

This formula was found by taking the formula for the volume of a cylinder and solving for h, or height. Knowing that V is 126 and the radius is 6, we can plug in our known variables in order to solve for h.

8 0

3 years ago

Read 2 more answers

Can two box plots have the same range and iqr

Salsk061 [2.6K]

Yes they can! Just because two plots have the same IQR and range, does not mean that the rest of the data has to be the exact same. For example, the median.

6 0

3 years ago

From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s

Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

60 out of 100 scores are passing scores, hence $n = 100, \pi = \frac{60}{100} = 0.6$

95% confidence level

So $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7$

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

5 0

3 years ago