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alisha [4.7K]
3 years ago
15

The Arc Electronic Company had an income of 90 million dollars last year. Suppose the mean income of firms in the same industry

as Arc for a year is 75 million dollars with a standard deviation of 11 million dollars. If incomes for this industry are distributed normally, what is the probability that a randomly selected firm will earn more than Arc did last year? Round your answer to four decimal places.
Mathematics
1 answer:
jok3333 [9.3K]3 years ago
8 0

Answer:

0.0869

Step-by-step explanation:

The arc electronic company had an income of 90 million dollars last year.

Mean(μ) = 75 million dollars

Standard deviation (σ) = 11 million dollars

Probability that the randomly selected will earn more than arc did last year = Pr(x>90)

Using normal distribution,

Z = (x - μ) / σ

Z = (90 - 75) / 11

Z = 15/11

Z = 1.36

From the normal distribution table, 1.36 = 0.4131

Φ(z) = 0.4131

Recall that when Z is positive, Pr(x>a) = 0.5 - Φ(z)

= 0.5 - 0.4131

= 0.0869

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Gene earns 2% interest after depositing $150 into his account , Option D.

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A function is a law that relates an independent variable and a dependent variable with each other.

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Option D , Gene earns 2% interest after depositing $150 into his account

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1 year ago
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Leni [432]
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3 years ago
joe has a piggy bank with $8.90 split upon nickels, dimes, and quarters. The piggy bank contains 76 coins in all. The number of
kozerog [31]

Answer:

There are 38 dimes, 22 nickels and 16 quarters.

Step-by-step explanation:

Let n, d and q represent the # of nickels, dimes and quarters respectively.

Then n + d + q = 76

The value of a nickel is $0.05; that of a dime is $0.10, and that of a quarter is $0.25.

Thus, the value of n nickels is $0.05n (and so on).

The total value of the coins is $0.05n + $0.10d + $0.25q = $8.90.

d = n + q allows us to eliminate d.

First, n + d + q = 76 becomes n + (n + q) + q = 76, and second:

$0.05n + $0.10(n + q) + $0.25q = $8.90.  Here we have succeeded in eliminating d from two different equations, and now we have these two different equations in two unknowns (n and q), which is solvable.

Simplifying both equations, we get:

2n + 2q = 76 and

5n + 10n + 10q + 25q = 890, or 15n + 35q = 890

Let's use the substitution method of solving linear equations:

Rewrite 2n  + 2q = 76 as n + q = 38, or n = 38 - q.  Substituting this result into the second equation, we get:

15(38 - q) + 35 q = 890, or

  570 - 15q + 35q = 890, or

   570 + 20 q = 890.  Then 20q = 890 - 570 = 320, and q = 320/20 = 16.

There are 16 quarters.  Thus, the number of nickels is n = 38 - 16 = 22.

Finally, since n + d + q = 76, 22 + d + 16 = 76, or:

22 + d = 60, or d = 60 - 22 = 38.

There are 38 dimes, 22 nickels and 16 quarters.

4 0
3 years ago
How many times does 17 go into 65 no decimals please only remainders if there is one.
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3 years ago
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The answer is simplified to 15
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