Answer:
<em>Area</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>garden</em><em>=</em><em>1</em><em>2</em><em>1</em><em> </em><em>square</em><em> </em><em>meter</em>
<em>perimeter</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>garden</em><em>=</em><em>4</em><em>4</em><em> </em><em>meter</em>
Step-by-step explanation:
Area of a square=side*side
=11*11
=<u>1</u><u>2</u><u>1</u><em><u>s</u></em><em><u>q</u></em><em><u>u</u></em><em><u>a</u></em><em><u>r</u></em><em><u>e</u></em><em><u> </u></em><em><u>meter</u></em>
Perimeter of a square garden=side*4
=11*4
=44 m
C, 60 hope this helps it helped me on my test
An arithmetic sequence starts with one number and you add the common difference to the previous term to get the current term
So...
f(x)=mx+b
m=common difference
b=starting point
f(11)=125=11m+b
-
f(1)=5=1m+b
--------
120=10m
Divide both sides by 10
12=m
Your common difference is 12.
At first we need to know how to find the distance between two parallel lines
The parallel lines which have the same slope
If we have two parallel lines ⇒ y₁ = mx + c₁ and y₂ = mx + c₂
So, the distance between y₁ and y₂ = d =

========================================================
Part (1):=======
<span>The distance between the lines
</span>
<span>
Y₁ = 3x + 10 and Y₂ = 3x - 20</span>
∴ m = 3 , c₁ = 10 and c₂ = -20
∴ d =

========================================================
Part (2):=======
<span>The distance between the lines
</span>
Y₁ = <span>3/2 x + 3/2</span> and Y₂ = <span>3/2 x - 5</span>
∴ m = 3/2 = 1.5 , c₁ = 3/2 = 1.5 and c₂ = -5
∴ d =
Hi!
Let's first expand the cotangent of theta.
You'll probably know that tangent will be "y/x", or
, and cotangent is the reciprocal of this, meaning that it is "x/y" or
.
That means that we are now given this equation.

That'll multiply to:

We'll want a common denominator to add by multiplying
to both top and bottom of the second term:


Pythagorean Identity states that
, so substitute that in:

Which simplifies to:

Hope this helps!