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Mice21 [21]
3 years ago
8

Wes rode his bike 30miles in 3 hrs what is the average speed

Mathematics
1 answer:
Effectus [21]3 years ago
3 0
If you just divide the 30 miles by the 3 hours then he was going 10 miles per hour.
You might be interested in
The sum of four times a number and five times another number is -28. The sum of nine times the first number and two times the se
dedylja [7]

Answer:

  -8

Step-by-step explanation:

If we let x and y represent the first and second numbers, respectively, we can write the problem statement as the equations ...

  • 4x +5y = -28
  • 9x +2y = 11

We can multiply the first equation by -9 and add 4 times the second equation to get an equation in y alone:

  -9(4x +5y) +4(9x +2y) = -9(-28) +4(11)

  -37y = 296 . . . . . simplify

  296/-37 = y = -8 . . . . . divide by the coefficient of y

The second number is -8.

7 0
4 years ago
9x9?????????????????????????
Len [333]
The answer to 9*9 is 81
3 0
3 years ago
Read 2 more answers
.. Carmen bakes and sells pies. She sells each pie for $12.99. The ingredients for 1 apple
Rainbow [258]

Answer:   $21.20

Step-by-step explanation:

first, find the profit carmen makes on each pie

12.99 - 8.75 = 4.24

now, we multiply that by the 5 pies that she sold to see what profit she made

4.24 x 5 = 21.2

$21.20

4 0
3 years ago
BRAINLIEST + 15 PTS TO WHOEVER HELPS!
Bumek [7]

Answer:

B) Observing how probability works with real items

Step-by-step explanation:

Just took the quiz :)

7 0
3 years ago
Which of the following are square roots of —8 + 8i/3? Check all that apply.
8090 [49]

Answer:

Options (2) and (3)

Step-by-step explanation:

Let, \sqrt{-8+8i\sqrt{3}}=(a+bi)

(\sqrt{-8+8i\sqrt{3}})^2=(a+bi)^2

-8 + 8i√3 = a² + b²i² + 2abi

-8 + 8i√3 = a² - b² + 2abi

By comparing both the sides of the equation,

a² - b² = -8 -------(1)

2ab = 8√3

ab = 4√3 ----------(2)

a = \frac{4\sqrt{3}}{b}

By substituting the value of a in equation (1),

(\frac{4\sqrt{3}}{b})^2-b^2=-8

\frac{48}{b^2}-b^2=-8

48 - b⁴ = -8b²

b⁴ - 8b² - 48 = 0

b⁴ - 12b² + 4b² - 48 = 0

b²(b² - 12) + 4(b² - 12) = 0

(b² + 4)(b² - 12) = 0

b² + 4 = 0 ⇒ b = ±√-4

                     b = ± 2i

b² - 12 = 0 ⇒ b = ±2√3

Since, a = \frac{4\sqrt{3}}{b}

For b = ±2i,

a = \frac{4\sqrt{3}}{\pm2i}

  = \pm\frac{2i\sqrt{3}}{(-1)}

  = \mp 2i\sqrt{3}

But a is real therefore, a ≠ ±2i√3.

For b = ±2√3

a = \frac{4\sqrt{3}}{\pm 2\sqrt{3}}

a = ±2

Therefore, (a + bi) = (2 + 2i√3) and (-2 - 2i√3)

Options (2) and (3) are the correct options.

6 0
3 years ago
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