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mezya [45]
3 years ago
9

The sum of four times a number and five times another number is -28. The sum of nine times the first number and two times the se

cond number is 11. What is the second number?
Mathematics
1 answer:
dedylja [7]3 years ago
7 0

Answer:

  -8

Step-by-step explanation:

If we let x and y represent the first and second numbers, respectively, we can write the problem statement as the equations ...

  • 4x +5y = -28
  • 9x +2y = 11

We can multiply the first equation by -9 and add 4 times the second equation to get an equation in y alone:

  -9(4x +5y) +4(9x +2y) = -9(-28) +4(11)

  -37y = 296 . . . . . simplify

  296/-37 = y = -8 . . . . . divide by the coefficient of y

The second number is -8.

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Answer:

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