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AleksandrR [38]
3 years ago
14

If M is the midpoint of line segment XY, find the coordinates of X if M(-3,1) and Y(-8,4)

Mathematics
1 answer:
lozanna [386]3 years ago
6 0

Answer:

The coordinates of point X are (-11/2, 5/2)

Step-by-step explanation:

To find the coordinates of X , we shall apply the midpoint formula;

Mathematically, that would be;

(x , y) = (x1 + x2)/2 , (y1 + y2)/2

From the question

x1 = -3 , x2 = -8

y1 = 1 , y2 = 4

So substituting these values, we have;

(x ,y) = (-3-8)/2, (1 + 4)/2

(x ,y) = -11/2, 5/2

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Sa = 2(pi)(r)(h) + 2(pi)(r^2) v = (pi)(r^2)(h) find the surface area and the volume.
LenKa [72]

If Sa=2πrh+2πr^{2}v=πr^{2}h then the surface area is πr^{2} h and volume is

(rh-2h)/2r.

Given Sa=2πrh+2πr^{2} v=πr^{2}h.

We have to find surface area and volume from the given expression.

Volume is basically amount of substance a container can hold in its capacity.

First we will find the value of v from the expression. Because they are in equal to each other, we can easily find the value of v.

2πrh+2πr^{2}v=πr^{2}h

Keeping the term containing v at left side and take all other to right side.

2πr^{2}v=πr^{2}h-2πrh

v=(πr^{2}h-2πrh)/2πr^{2}

v=πr^{2} h/2πr^{2}-2πrh/2πr^{2}

v=h/2-h/r

v=h(r-2)/2r

Put the value of v in Sa=2πrh+2πr^{2} v

Sa=2πrh+2πr^{2}*h(r-2)/2r

=2πrh+2πrh(r-2)/2

=2πrh+πrh(r-2)

=2πrh+πr^{2}h-2πrh

=πr^{2}h

Hence surface area is πr^{2}h and volume is h(r-2)/2.

Learn more about surface area at brainly.com/question/16519513

#SPJ4

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Step-by-step explanation:

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