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VashaNatasha [74]
2 years ago
15

HELP ASAP PLEASEEE.​

Mathematics
1 answer:
Troyanec [42]2 years ago
8 0

Please mark Brainliest. Plz.

Answer:

x^2 = 25    x = 5, -5

2x^2 = 98    x = 7, -7

x^2 + 64 = 0    x = 8i, -8i

9x^2 - 16 = 0    x = 4/3, -4/3

x^2 + 9 = 25    x = 4, -4

(x-2)^2 = 25    x = 7, -3

(x-2)^2 +9 = 25    x = 6, -2

4(x-2)^2 +9 = 25    x = 4, 0

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The equation, 3x2 + 6x + 3y2 + 7y + 4 = 0, represents a conic.
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Answer: Circle

Step-by-step explanation:

Check the variables' degrees and their coefficients' signs to determine the type of the conic.

7 0
3 years ago
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Ellis is painting wooden fenceposts before putti by then in his yard. They are each 5 feet tall and have a diameter of 1 foot. T
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Answer:

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3 0
2 years ago
What’s is the answer
kvasek [131]

When you are multiplying an exponent directly into a number/variable with an exponent, you multiply the exponents together.

For example:

(x^{2} )^{3} = x^6

(x^{3} )^5=x^{15}


When you are multiplying a variable with an exponent by another variable with an exponent, you add the exponents together.

For example:

(x^{2} )(x^{3})=x^{5}

(x^{1} )(x^{2})=x^{3}


(\frac{(x^{-3})(y^{2})}{(x^{4})(y^{6})} )^{3}=\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}

You multiply 3 into each exponent in the numerator and the denominator

\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}= \frac{y^{6}}{(x^{9})(x^{12})(y^{18})}

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

\frac{y^{6}}{(x^{21})(y^{18})} = \frac{1}{(x^{21})(y^{12})}


When you have something like this:

\frac{x^{2}}{x^5}

You subtract the exponents together, so:

\frac{x^2}{x^5} = x^{2-5} = x^{-3} = \frac{1}{x^3}


Your answer is the second option

3 0
3 years ago
Khan Academy math question
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Answer:

the answer is 0 you're welcome bye

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Calculate the following absolute value |-1-1+2|-|-1+2|-|-2|
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-3

Hope This Helps!

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