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hodyreva [135]
3 years ago
13

Just wondering is 71 a PRIME number? ≡≡≡

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
7 0
Yes 71 is a Prime Number
maxonik [38]3 years ago
7 0
Yes it is. When a number has more than two factors it is called a composite number
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4 2/5 + 3 1/10 + 2 3/5
ElenaW [278]

Answer:

10 1/10

Step-by-step explanation:

22/5 + 31/10 + 13/5

44/10 + 31/10 + 26/10

101/10

10 1/10

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2 years ago
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Solve the equation.<br>5x + 8 - 3x = -10<br>x = -9<br>X = -1<br>x = 1<br>X = 9<br>Cand​
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Here is how I solved it and the answer

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3 years ago
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Tyler has 120 linear feet of fencing to put around his garden. If he uses the fence to border a rectangular garden, what is the
Travka [436]

Answer:

The maximum area is 900\ ft^{2}

Step-by-step explanation:

Let

x----> the length of rectangle

y---> the width of rectangle

we know that

The perimeter of rectangle is equal to

P=2(x+y)

we have

P=120\ ft

so

120=2(x+y)

60=(x+y)

y=60-x------> equation A

Remember that

The area of rectangle is equal to

A=xy -----> equation B

substitute equation A in equation B

A=x(60-x)

A=-x^{2} +60x

This is a vertical parabola open downward

The vertex is a maximum

The y-coordinate of the vertex of the graph is the maximum area of the garden and the x-coordinate is the length for the maximum area

using a graphing tool

The vertex is the point (30,900)

see the attached figure

Find the value of y

y=60-x ----->  y=60-30=30\ ft

The dimensions of the rectangular garden is 30\ ft by 30\ ft

For a maximum area the garden is a square

The maximum area is 900\ ft^{2}

5 0
4 years ago
Starting at 6 a.m. every morning, Matilda receives text messages on her cell phone from her mother, her best friend, and her bro
Dafna1 [17]

Answer:

a) 0.0013 = 0.13% probability that by 7:30 a.m. Mary receives exactly four messages – two of her best friend and two of her mother.

b) 1.6 \times 10^{-9} probability that there are no typos in the text messages Matilda receives between 2 p.m. and 5 p.m.

Step-by-step explanation:

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

A) Find the probability that by 7:30 a.m. Mary receives exactly four messages – two of her best friend and two of her mother.

Two from the best friend:

Her best friend sends a message once every 10 minutes.

From 6 to 7:30, there is an hour and a half, that is, 90 minutes, so the mean for her best friend is \mu = \frac{90}{10} = 9

Two messages is P(X = 2). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 2) = \frac{e^{-9}*9^{2}}{(2)!} = 0.0050

Two from the mother:

Message every hour = 60 minutes. So \mu = \frac{90}{60} = 1.5. This is P(X = 2).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 2) = \frac{e^{-1.5}*1.5^{2}}{(2)!} = 0.2510

Two of her best friend and two of her mother:

Independent events, so the probability of both happening is the multiplication of their separate probabilities.

p = 0.005*0.251 = 0.0013

0.0013 = 0.13% probability that by 7:30 a.m. Mary receives exactly four messages – two of her best friend and two of her mother.

B) With a chance of 75% a text message contains a typo independent of the sender. Find the probability that there are no typos in the text messages Matilda receives between 2 p.m. and 5 p.m.

In 3 hours, she is expected to receive:

3*60/10 = 18 messages from her best friend.

3*60/60 = 3 messages from her mother.

3*60/30 = 6 messages from her brother.

In total, 27 messages.

75% probability of a typo, so \mu = 0.75*27 = 20.25

This is P(X = 0).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-20.25}*20.25^{0}}{(0)!} = 1.6 \times 10^{-9}

1.6 \times 10^{-9} probability that there are no typos in the text messages Matilda receives between 2 p.m. and 5 p.m.

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3 years ago
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One solution is the y intercept (0,1/2)
3 0
3 years ago
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