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3 years ago

9

The distance around a park is 3/2 miles. Noah rode his bicycle around the park for a total of 3 miles. How many times around the

park did he ride? Ill mark you brainliest:3

2 answers:

zzz [600]3 years ago

5 0

Answer:

2 times

Step-by-step explanation:

Ann [662]3 years ago

4 0

Answer:

2 times

Step-by-step explanation:

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3 years ago

What is the total number of different 10-letter arrangements that can be formed using the letters in the word FORGETTING?

velikii [3]

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2 years ago

Can someone help me understand squares,cubes,and roots with example problems please

erastova [34]

when someone says a number squared or cubed, or to the certain power, it means how many times you multiply the base number by itself that many times, for example

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3 years ago

Milo has 2 hours of free time. He spends 2/4 of an hour with his dog. He spends 3/4 of an hour drawing. What fraction of an hour

blagie [28]

Answer: 3/4 of an hour left.

Step-by-step explanation:

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3 years ago

Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste

lidiya [134]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$ In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$ And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

Solution to the problem

For this case we have the following distribution given:

X 3 4 5 6

P(X) 0.07 0.4 0.25 0.28

We can calculate the mean with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$

In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$

And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

3 0

3 years ago