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3 years ago

Describe an example where materials are prepared as fluids so that they can be moved more easily.

Chemistry

1 answer:

OleMash [197]3 years ago

7 0

Liquefied Natural Gas

Explanation:

Gases are usually liquefied in the downstream sector during crude processing. These natural gases are products of distillation of crude oil in fractionating columns. Some of them are also found in geological formations.

To easily transport these gases, they are liquefied in vessels that carries them from one place to another.
Liquefaction is the process of converting a gas or solid into a liquid form.
Gases are usually compressed under very high pressure into vessels through which can make them easier to transport.
Gases do not have a fixed volume and they typically assume the volume of any container they are taken into.

Learn more:

Natural gas brainly.com/question/4344417

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Combustion reactions are characterized by the reaction of a substance with

pashok25 [27]

Answer: Combustion reactions are characterized by the reaction of a substance with O2 to form one or more oxygen, often water. Combustion reactions emit heat, and they are important because most of society's energy is derived from them. Ex.: CH4 (g) + 2O2 (g) -- CO2 (g) + 2H2O (g)

Explanation: I hope thus helps UwU

8 0

3 years ago

Read 2 more answers

Be sure to answer all parts. The sulfate ion can be represented with four S―O bonds or with two S―O and two S═O bonds. (a) Which

VMariaS [17]

Answer:

a) Representation - (in attachment)

b) Tetrahedral geometry and

c) $sp^{3}$ hybrid orbitals invovle sigma bonding.

$\pi$ orbitals are formed by the overlapping of d-orbitals of sulfur with p-orbitals of oxygen.

Explanation:

Representation in attachment.

The overall charge in the both structures are -2. The structure (b) is favored by the resonance structures since the formal charge with in the species are remained.

Therefore, structure (b) is the better representation of sulfate ion.

In sulfate ion, sulfur atom is attached with four different oxygen atoms. According to the VSEPR theory , the sufate ion has tetrahedral geometry.

There is four sigma bonds and zero lone pairs present on the central metal atom.

Hence, the hybridization of the sulfur atom is $sp^{3}$

The s and p orbitals of sulfur invovles hybridization and form sigma bonds.The orbitals of sulfur involves $\pi$ bonding.

Therefore, $\pi$ bonds are formed by the overlapping of d-orbitals of sulfur with p-orbitals of oxygen.

5 0

4 years ago

A series of enzymes catalyze the reactions in the metabolic pathway X → Y → Z → A. Product A binds to the enzyme that converts X

Gnom [1K]

The question is incomplete as it does not have the option which are:

A. A coenzyme.

B. An allosteric inhibitor.

C. The substrate.

D. An intermediate.

E. A competitive inhibitor.

Answer:

An allosteric inhibitor.

Explanation:

An allosteric inhibitor is a molecule which binds to the site other than the active site but inhibits the action of the Enzyme and thus the product.

The allosteric inhibitor is considered a non-competitive inhibitor which after binding to the enzyme cause some conformational changes which further changes the structure of the active site and thus substrate no longer binds the enzyme. This molecule thus inhibits the production.

Thus, An allosteric inhibitor is correct.

7 0

3 years ago

Which of the following has the most stable nucleus? Fe He U B

Harlamova29_29 [7]

Answer:

Explanation:

Ferrum [Iron] has the most stable nucleus because of binding energy per nucleon. Although Uranium is another possibility, in this case, it is more radioactive than Iron. It disintegrates very swiftly that all is done so, just to achieve stability.

I hope this helps you out alot, and as always, I am joyous to assist anyone at any time.

3 0

3 years ago

Phosphorus-32 is radioactive and has a half life of 14.3 days. What percentage of a sample would be left after 12.6 days

nadya68 [22]

Answer:

There is 54.29 % sample left after 12.6 days

Explanation:

Step 1: Data given

Half life time = 14.3 days

Time left = 12.6 days

Suppose the original amount is 100.00 grams

Step 2: Calculate the percentage left

X = 100 / 2^n

⇒ with X = The amount of sample after 12.6 days

⇒ with n = (time passed / half-life time) = (12.6/14.3)

X = 100 / 2^(12.6/14.3)

X = 54.29

There is 54.29 % sample left after 12.6 days

8 0

3 years ago