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AlekseyPX
3 years ago
5

Chemistry student needs 15.0 g of painting for an experiment by consulting the CRC handbook of chemistry and physiology the stud

ent discovers that the density is 0.626 g per centimeter to the -3rd calculate the volume of pentane the student should pour out
Chemistry
1 answer:
nalin [4]3 years ago
8 0

Answer:

v = 23.96 cm³

Explanation:

Given data:

Mass = 15.0 g

Density = 0.626 g/cm³

Volume = ?

Solution:

Formula:

D=m/v

D= density

m=mass

V=volume

Now we will put the values in formula:

d = m/v

v = m/d

v = 15 g / 0.626 g/cm³

v = 23.96 cm³

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Status: No credit Points earned: 0.00/1.00
DIA [1.3K]

Answer:

Cu₂O.

Explanation:

copper = 7.298

copper oxide = 8.217

oxygen in copper oxide = .919 g

7.298 g of copper = 7.298 / 63.5 mole of copper

= .1149 mole of copper

.919 g of oxygen = .919 / 16 mole of oxygen

= .0574 mole of oxygen

ratio of mole of copper and oxygen

= .1149 / .0574 = 2

formula of copper oxide = Cu₂O.

8 0
4 years ago
Where are the most gases located on the periodic table?
Vlada [557]

Answer:

They are mostly located in group 18 (column 18), or far right

4 0
3 years ago
Which of the following describes the melting point of a solid?
yKpoI14uk [10]

The melting point (or, rarely, liquefaction point) of a solid is the temperature at which it changes state from solid to liquid at atmospheric pressure. At the melting point the solid and liquid phase exist in equilibrium. The melting point of a substance depends on pressure and is usually specified at standard pressure.

8 0
4 years ago
Read 2 more answers
Examine the equation.
Rina8888 [55]
The answer is 2
i hope it helps
6 0
4 years ago
Read 2 more answers
A block of ice sitting at 0 °C is completely melted by adding 584.5 J of heat to it. If the latent heat of fusion for ice is 334
Likurg_2 [28]

Answer:

mass of ice is 1.75

Explanation:

Using, the formula given in the question,

m = Q/HΔf.................. Equation 1

Where Q = Heat, m = mass of ice, HΔf = Latent heat of fussion of for ice.

From the question,

Given: Q = 584.5 J, HΔf = 334 J/g

Substitute these values into equation 2

m = 584.5/334

m = 1.75 kg.

Hence the mass of ice without unit is 1.75

7 0
3 years ago
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