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Mekhanik [1.2K]
4 years ago
14

What is the volume of this oblique cone?

Mathematics
2 answers:
castortr0y [4]4 years ago
7 0
Hey I tried, hope it helps... can't work it out, all the best

Fofino [41]4 years ago
5 0

Answer:

D. 120\pi\text{ cm}^3

Step-by-step explanation:

We have been given a diagram of oblique prism and we are asked to find the volume of our given oblique cone.

Since we know that volume of prism equals 1/3 of the base area times height of the prism.

As base of the prism is circle, so volume of prism will be:

\text{Volume of oblique prism}=\frac{1}{3}\times \pi r^2\times h

Upon substituting our given values in volume formula we will get,

\text{Volume of oblique prism}=\frac{1}{3}\times \pi\times (6\text{ cm})^2\times 10\text{ cm}

\text{Volume of oblique prism}=\frac{1}{3}\times \pi\times 36\text{ cm}^2\times 10\text{ cm}

\text{Volume of oblique prism}=\pi\times 12\text{ cm}^2\times 10\text{ cm}

\text{Volume of oblique prism}=120\pi\text{ cm}^3

Therefore, the volume of our given oblique prism will be 120\pi\text{ cm}^3 and option D is the correct choice.

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We have that

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N 2) 

a²<span> + 9a + 14 = 0
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Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 9a)=-14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² +9a+20.25)=-14+20.25

Rewrite as perfect squares

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a1=-4.5+√6.25-----> a1=-2

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the solution problem N 2 is the pair {-2,-7}

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a² + 3a − 10 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

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Rewrite as perfect squares

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a1=-1.5+√12.25-----> a1=2

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the solution problem N 3 is the pair {2, -5}


N 4)

a²<span> + 5a − 14 = 0
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Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 5a) =14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² + 5a+6.25) =14+6.25

Rewrite as perfect squares

(a+2.5)² =20.25-------> (a+2.5)=(+/-)√20.25

a1=-2.5+√20.25-----> a1=2

a2=-2.5-√20.25-----> a2=-7

the solution problem N 4 is the pair {2, -7}


N 5) 

a² − 5a − 14 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 5a)=14

Complete the square  Remember to balance the equation by adding the same constants to each side 

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