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pishuonlain [190]
3 years ago
6

Which functions domains consist of all real numbers except -2?

Mathematics
2 answers:
slamgirl [31]3 years ago
8 0
<span>I believe its f(x)=1/x+2. Are there choices?

</span>
katrin2010 [14]3 years ago
6 0
Is -2 the only point of reference given? 
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Calculate the product using partial product 200 times 20.7
Lady_Fox [76]

Answer:

4140

Step-by-step explanation:

5 0
3 years ago
Find an equation for the tangent to the curve at the given point. y=x^2+2 ; (2, 6)
Zinaida [17]
1) Find the derivative y'=2x and y'(2)=2\cdot2=4.
2) The equation of the tangent line is y=y'(x_0)(x-x_0)+y_0, so at point (2,6): x_0=2 \\ y_0=6 and
y=4(x-2)+6
y=4x-2 -the equation of the tangent line at point (2,6).

5 0
3 years ago
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Which value is not in the range of the function? А. 0<br> B. 3 <br>C. 4 <br>D. 5​
r-ruslan [8.4K]

Answer:

B

Step-by-step explanation:

5 0
2 years ago
The Niagara Falls ferris wheel has a diameter of 48 meters, and one revolution takes 2.25 minutes to complete. Riders can see Ni
Yanka [14]

The time intervals when the riders could see Niagara falls are; 0.834 < t < 1.416 and (3.084, 3.666)

<h3>How to interpret Cycle Graphs?</h3>

From the diagram attached, we can say that;

Period = 2π/k

where;

k = 2π/2.25

k = 8π/9

Thus;

h(t) = -(48/2) cos (8π/9)t + ((48/2) + 0.5)

h(t) = -24cos (8π/9)t + 24.5

Riders can see Niagara falls if they are higher than 41 meters above the ground. Thus;

41 = -24cos (8π/9)t + 24.5

41 - 24.5 = -24cos (8π/9)t

16.5 = -24cos (8π/9)t

-0.6875 = cos (8π/9)t

cos⁻¹0.6875 = (8π/9)t

t = 0.834 min

Thus, time interval is between;

0.834 < t < (2.25 - 0.834)

⇒ 0.834 < t < 1.416 and

(2.25 + 0.834) < t < (2.25 + 1.416)

⇒ (3.084, 3.666)

Read more about Cycle Graphs at; brainly.com/question/24461724

#SPJ1

4 0
2 years ago
Use a table of values with at least 5 values to graph the following function:
34kurt

The given expression :

y=(\frac{1}{2})^x

For coordinates:

put x = 0 then :

\begin{gathered} y=(\frac{1}{2})^0 \\ y=1 \end{gathered}

Coordinate : (x, y) = (0, 1)

Put x= 1 and simplify :

\begin{gathered} y=(\frac{1}{2})^1 \\ y=\frac{1}{2} \\ y=0.5 \end{gathered}

Coordinate : (x, y) = ( 1, 0.5)

Put x = (-2) and simplify :

\begin{gathered} y=(\frac{1}{2})^{-2} \\ y=\frac{1^{-2}}{2^{-2}} \\ y=\frac{2^2}{1^2} \\ y=2^2 \\ y=4 \end{gathered}

Coordinate : (x, y) = ( -2, 4)

Put x = (-3) and simplify :

\begin{gathered} y=(\frac{1}{2})^{-3} \\ y=\frac{1^{-3}}{2^{-3}} \\ y=\frac{2^3}{1^3} \\ y=2^3 \\ y=8 \end{gathered}

Coordinate : (x, y) = (-3, 8)

Substitute x = (-1) and simplify :

\begin{gathered} y=(\frac{1}{2})^x \\ y=(\frac{1}{2})^{-1} \\ y=\frac{1^{-1}}{2^{-1}} \\ y=\frac{2}{1} \\ y=2 \end{gathered}

Coordinate : (x, y) = ( -1, 2)

So, the coordinates are :

The graph is :

4 0
1 year ago
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