That figure is made up of 3 shapes.
A square, a rectangle, a semicircle.
The square has a side of 6 ft.
The semicircle has a radius of 4 ft.
The rectangle's width is the diameter of the semicircle, so it is 8 ft. The length of the rectangle is 18 ft.
Square:
A = s^2 = (6 ft)^2 = 36 ft^2
Rectangle:
A = LW = 18 ft * 8 ft = 144 ft^2
Semicircle:
A = (1/2) * pi * r^2 = (1/2) * pi * (4 ft)^2 = (1/2) * pi * 16 ft^2 = 8pi ft^2
Total area:
A = 36 ft^2 + 144 ft^2 + 8pi ft^2
A = (180 + 8pi) ft^2
Answer:



Step-by-step explanation:
Given

Required
Select true inequalities

Subtract 2.1 from both sides

This is true

Open brackets

Subtract 4 from both sides




This is also true
Answer:
12.5
Step-by-step explanation:
see attached image
Answer:
x=60.9°
Step-by-step explanation:
Given that the height of ball from the ground is 150ft
The base of the pole with the ball is 80 ft from where Trey is standing
Trey's horizontal line of sight is 6 feet above ground, then;
The height of ball from Trey's horizontal line of sight is;
150ft-6ft = 144ft
To find the angle x, assume a triangle with a base of 80 ft , a height of 144 ft and a slant height that represent the line of sight at an angle x
To get angle x , you apply the tangent of an angle formula where;
tan Ф°= length of opposite site of the angle/length of the adjacent side of the angle
tan x°= 144/80
tan x°= 1.8
x°= tan⁻(1.8)
x°=60.9°