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Reptile [31]
3 years ago
13

What square footage of artificial grass is needed to cover this portion of the course?

Mathematics
2 answers:
Wewaii [24]3 years ago
7 0
That figure is made up of 3 shapes.
A square, a rectangle, a semicircle.
The square has a side of 6 ft.
The semicircle has a radius of 4 ft.
The rectangle's width is the diameter of the semicircle, so it is 8 ft. The length of the rectangle is 18 ft.

Square:
A = s^2 = (6 ft)^2 = 36 ft^2

Rectangle:
A = LW = 18 ft * 8 ft = 144 ft^2

Semicircle:
A = (1/2) * pi * r^2 = (1/2) * pi * (4 ft)^2 = (1/2) * pi * 16 ft^2 = 8pi ft^2

Total area:
A = 36 ft^2 + 144 ft^2 + 8pi ft^2

A = (180 + 8pi) ft^2
Hitman42 [59]3 years ago
5 0

Answer:

the answer is (8pi+180)

Step-by-step explanation:

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Why does the multiplication property of equality not allow us to divide both sides of an equation by zero?​
Anna71 [15]

First of all, recall that division by zero is undefined; it's nonsensical; it's just not allowed.So zero certainly needs to be excluded when dividing.

But what about multiplying by zero?

The problem is that multiplying by zero can change the truth of an equation:

It can take a false equation to a true equation.

To see this, consider the false equation ‘

2 = 3

Multiplying both sides by zero results in the new equation

2 ⋅ 0 = 3 ⋅0 (that is, ‘0 = 0’), which is true.

6 0
3 years ago
A constant force of 85 N accelerates towards a 10 kg box from a speed of 3.0 m/s to a speed of 7.0 m/s as it goes 14 m along a h
photoshop1234 [79]

Answer:

Step-by-step explanation:

Let us find the acceleration of box .  

v² = u² + 2as

Putting the values

7² = 3² + 2 a x 14

a = 1.43 m /s²

If coefficient of friction be μ

force of friction = μ mg

= μ x 10 x 9.8

= 98μ

Net force pushing the box

= 85 - 98μ

Applying newton's second law

85 - 98μ = 10 x 1.43

98μ = 85 - 14.3

μ = .72

5 0
3 years ago
BRAINLIEST FOR QUICKEST<br> Please help with this question!!
GarryVolchara [31]

Answer:

A and B and C and D

Step-by-step explanation:

Letters

6 0
2 years ago
Read 2 more answers
A building casts a shadow 47 feet long. At the same time, a 38‐foot‐tall flagpole casts a shadow 9.4 feet long. What is the heig
alexdok [17]

210 feet  To answer this question you need to know the ratio of shadow with the actual object. In this case, 42 feet flagpole cast 9.4 feet shadow. Then the ratio is:

42feet/9.4 feet= 4.468

That means the actual height is 4.468 times of shadow length. After that, you can multiply the ratio with the shadow to know the object actual size. It would be: 47 feet x 4.468=  210 feet.

7 0
3 years ago
Find the length of side a.<br>A. 2 <br>B. 3 <br>C. 34<br>D. 9​
Tresset [83]
It’s B


You need to use the Pythagorean theorem which is a squared + b squared = c squared

So a^2+4^2=5^2
Simplified that would be a^2 + 16 = 25

Subtract 16 from both sides
A^2=9

And the square root of nine is 3
6 0
3 years ago
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