What square footage of artificial grass is needed to cover this portion of the course?

Mathematics

2 answers:

Wewaii [24]3 years ago

7 0

That figure is made up of 3 shapes.
A square, a rectangle, a semicircle.
The square has a side of 6 ft.
The semicircle has a radius of 4 ft.
The rectangle's width is the diameter of the semicircle, so it is 8 ft. The length of the rectangle is 18 ft.

Square:
A = s^2 = (6 ft)^2 = 36 ft^2

Rectangle:
A = LW = 18 ft * 8 ft = 144 ft^2

Semicircle:
A = (1/2) * pi * r^2 = (1/2) * pi * (4 ft)^2 = (1/2) * pi * 16 ft^2 = 8pi ft^2

Total area:
A = 36 ft^2 + 144 ft^2 + 8pi ft^2

A = (180 + 8pi) ft^2

Hitman42 [59]3 years ago

5 0

Answer:

the answer is (8pi+180)

Step-by-step explanation:

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An eighth grade class rolls a number cube 50 times. The number cube has sides

marshall27 [118]

Answer:

9/25

Step-by-step explanation:

Number of Trials =50

<u>Outcomes Less than 4</u>

Frequency of 1=6

Frequency of 2=4

Frequency of 3=8

Total =6+4+8=18

Relative frequency for "roll a number less than 4" =18/50=9/25

3 0

3 years ago

An olympic hurdler accelerates at a rate of 15.5 m/s2 . what is the rate in miles/min2 ? 1. 6.89 miles/min2 2. 31.8 miles/min2 3

Tom [10]

For this case we have to take into account the following conversions:
$1 mile = 1609.34 meters

1 minute = 60 seconds$
Let's first transform the expression to miles per seconds squared:
$(15.5) * (1 / 1609.34) = 0.009631277 mi / s ^ 2
$
Then, we transform the result to miles per minute squared.
We have then:
$(0.009631277) * (60) ^ 2 = 34.7 mi / min ^ 2
$
Answer:
the rate in miles/min^2 is:
$34.7 mi / min ^ 2$