What square footage of artificial grass is needed to cover this portion of the course?

Mathematics

2 answers:

Wewaii [24]3 years ago

7 0

That figure is made up of 3 shapes.
A square, a rectangle, a semicircle.
The square has a side of 6 ft.
The semicircle has a radius of 4 ft.
The rectangle's width is the diameter of the semicircle, so it is 8 ft. The length of the rectangle is 18 ft.

Square:
A = s^2 = (6 ft)^2 = 36 ft^2

Rectangle:
A = LW = 18 ft * 8 ft = 144 ft^2

Semicircle:
A = (1/2) * pi * r^2 = (1/2) * pi * (4 ft)^2 = (1/2) * pi * 16 ft^2 = 8pi ft^2

Total area:
A = 36 ft^2 + 144 ft^2 + 8pi ft^2

A = (180 + 8pi) ft^2

Hitman42 [59]3 years ago

5 0

Answer:

the answer is (8pi+180)

Step-by-step explanation:

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