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3 years ago

Using the equation below create a model to slove 4+d=11

Mathematics

1 answer:

Maru [420]3 years ago

3 0

4 + d = 11
-4 -4
d = 7

Hope this helps!

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What is the correct expanded form and value of (1 over 5 ) 4

slavikrds [6]

Answer:

1/625

Step-by-step explanation:

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3 years ago

Sec^2x-1/sec^2x=sin^2x

disa [49]

$\dfrac{\sec^2x-1}{\sec^2x}=1-\dfrac1{\sec^2x}=1-\cos^2x=\sin^2x$

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4 years ago

Use the Law of Sines to solve the triangle. Round your answers to two decimal places.

mario62 [17]

Answer:

Step-by-step explanation:

The Law of Sines is

$\frac{sinA}{a}=\frac{sinB}{b}=\frac{sinC}{c}$

Filling in what we are given:

$\frac{sin(110.8)}{25.3}=\frac{sin(18.2)}{c}$

Cross multiply to get

$csin(110.8)=25.3sin(18.2)$ and divide to solve for side c:

$c=\frac{25.3sin(18.2)}{sin(110.8)}$ which gives you that

c = 8.45

We know that angle B has to be the difference between 180 and angle A and angle C, so

angle B = 51

Now we can solve for side b:

$\frac{sin(110.8)}{25.3}=\frac{sin(51)}{b}$ and

$b=\frac{25.3sin(51)}{sin(110.8)}$ and

b = 21.03

8 0

3 years ago

The area of the right triangle shown is 24 square feet.

Goryan [66]

The equations used to find the length of leg of triangle are:

$0.5x(x+2) = 24\\\\x^2+2x-48=0\\\\x^2+(x+2)^2 = 100$

Solution:

From given,

Area of right triangle = 24 square feet

Also from given figure in question (attached below )

base = x and height = x + 2

The area of triangle is given by formula:

$Area = \frac{1}{2} \times base \times height$

Substituting the values we get,

$24 = \frac{1}{2} \times x \times (x+2)\\\\24 = 0.5x(x + 2)\\\\48 = x(x+2)\\\\x^2 + 2x - 48 = 0\\\\$

Also, the above equation can be written as,

$x^2 + (x+2)^2 =100$

Thus the equations used to find the length of leg of triangle are:

$0.5x(x+2) = 24\\\\x^2+2x-48=0\\\\x^2+(x+2)^2 = 100$

4 0

3 years ago

Read 2 more answers

Which of the following is the ordered pair for point E?A.(2,-4)

inysia [295]

Answer:

its (-2,4)

gimme brainliest plz :)

Step-by-step explanation:

3 0

3 years ago